It takes a boat going upstream 3 hours to cover the same distance, as it would cover in 2

Sally and Anne went to the movies. They each purchased a drink. They also bought one popcorn and one veggie cup to share. Each w

Reika [66]

Answer:

I just took the assignment for this i was correct but this is what i put First you would evulate what is in parenthisis and then evalate what's in them so you do 3.50 and you add 1.74 and that equals 5.25. Then you add 9 plus 1.34 and you get 10.34 and after that you do 5.25 and 10.34 and that equals 15.59 then u take the 1/2 and add that and in total you get 16.09 sample answer was... Sample Response: First, add the decimals in the parentheses. Next, multiply that number by 0.5. Finally, add all the decimal numbers.

Hope this helps have a nice day just rember the step shown in video that's all u had to includde in this answer really but rember pendas hope i help thanks

4 0

4 years ago

Read 2 more answers

Tensile-strength tests were carried out on two different grades of wire rod. Grade 1 has 10 observations yielding a sample mean

earnstyle [38]

Answer:

$t=\frac{(1085 -1034)-(0)}{57.646\sqrt{\frac{1}{10}+\frac{1}{15}}}=2.167$

$p_v =2*P(t_{23}$

We see that the p value is lower than the significance level provided of 0.05 so then we have enough evidence to conclude that the true means are different at 5% of significance.

Step-by-step explanation:

Data given

$n_1 =10$ represent the sample size for group 1

$n_2 =15$ represent the sample size for group 2

$\bar X_1 =1085$ represent the sample mean for the group 1

$\bar X_2 =1034$ represent the sample mean for the group 2

$s_1=52$ represent the sample standard deviation for group 1

$s_2=61$ represent the sample standard deviation for group 2

We are assuming that the two samples are normally distributed with equal variances and that means:

$\sigma^2_1 =\sigma^2_2 =\sigma^2$

System of hypothesis

Null hypothesis: $\mu_1 = \mu_2$

Alternative hypothesis: $\mu_1 \neq \mu_2$

The statistic is given by:

$t=\frac{(\bar X_1 -\bar X_2)-(\mu_{1}-\mu_2)}{S_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2}}}$

The degrees of freedom are given by:

$n_1+n_2 -2$

And the pooled variance is:

$S^2_p =\frac{(n_1-1)S^2_1 +(n_2 -1)S^2_2}{n_1 +n_2 -2}$

Replacing we got:

$S^2_p =\frac{(10-1)(52)^2 +(15 -1)(61)^2}{10 +15 -2}=3323.043$

And the deviation would be:

$S_p=57.646$

The degrees of freedom are:

$df=10+15-2=23$

The statistic would be:

$t=\frac{(1085 -1034)-(0)}{57.646\sqrt{\frac{1}{10}+\frac{1}{15}}}=2.167$

The p value would be

$p_v =2*P(t_{23}$

We see that the p value is lower than the significance level provided of 0.05 so then we have enough evidence to conclude that the true means are different at 5% of significance.

6 0

3 years ago

graph the line that passes through the points (-3,-7) and (-2,-7) and determine the equation of the line

Lera25 [3.4K]

Answer:

y = -7

Step-by-step explanation:

y2 - y1 / x2 - x1

-7 - (-7) / -2 - (-3)

0/1

= 0

y = 0x + b

-7 = 0(-2) + b

-7 = 0 + b

-7 = b

3 0

3 years ago

Simplify the expression.<br> : 8 - 2(3)

Maru [420]

Answer: the answer is just 2

7 0

3 years ago

Can u pls help me with this question

saul85 [17]

Answer:

The answer is D, 43 $\frac{1}{2}$

Step-by-step explanation:

If the pile gets bigger by 8 $\frac{7}{12}$ each week, and you want to find out how big the pile is after 3 weeks, then you have to multiply 8 $\frac{7}{12\\}$ by 3 to find out how much the pile increased by.

8 $\frac{7}{12\\}$ × 3 = 25 $\frac{3}{4}$

Now, you need to add this to your initial value to get the answer.

25 $\frac{3}{4}$ + 17 $\frac{3}{4}$ = 42 $\frac{6}{4}$

Now simplify.

43 $\frac{1}{2}$

3 0

3 years ago