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2 years ago

Function g is define by g(x) = 3(x+8). What is the value of g(12)

1 answer:

5 0

When given a function and asked to find the value of a number, in this case g(12), simply plug 12 into all x places in the equation:

g(12)=3(12+8)

g(12)=36+24

g(12)=60

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It appears that people who are mildly obese are less active than leaner people. One study looked at the average number of minute

NemiM [27]

Answer:

a) 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

b) 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

Step-by-step explanation:

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $\frac{\sigma}{\sqrt{n}}$ .

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Mildly obese

Normally distributed with mean 373 minutes and standard deviation 67 minutes. So $\mu = 373, \sigma = 67$

A) What is the probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes?

So $n = 5, s = \frac{67}{\sqrt{5}} = 29.96$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 373}{29.96}$

$Z = 1.23$

$Z = 1.23$ has a pvalue of 0.8907.

So there is a 1-0.8907 = 0.1093 = 10.93% probability that the mean number of minutes of daily activity of the 5 mildly obese people exceeds 420 minutes.

Lean

Normally distributed with mean 526 minutes and standard deviation 107 minutes. So $\mu = 526, \sigma = 107$

B) What is the probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes?

So $n = 5, s = \frac{107}{\sqrt{5}} = 47.86$

This probability is 1 subtracted by the pvalue of Z when X = 410.

$Z = \frac{X - \mu}{s}$

$Z = \frac{410 - 526}{47.86}$

$Z = -2.42$

$Z = -2.42$ has a pvalue of 0.0078.

So there is a 1-0.0078 = 0.9922 = 99.22% probability that the mean number of minutes of daily activity of the 5 lean people exceeds 420 minutes.

7 0

2 years ago

Help please fast:):):):):):

pochemuha

C. is not a function since all the F9x) numbers are identical

7 0

2 years ago

Read 2 more answers

DECK is a parallelogram with m∠1 = 20°, m∠(<img src="https://tex.z-dn.net/?f=x%5E%7B2%7D" id="TexFormula1" title="x^{2}" alt="x^

maw [93]

9514 1404 393

Answer:

m∠2 = 16° or 25°

Step-by-step explanation:

The sum of angles 1 and 2 is congruent to angle CED.

20° +(x^2)° = (9x)°

x^2 -9x +20 = 0 . . . . . divide by °, put in standard form

(x -5)(x -4) = 0 . . . . . . . factor

x = 5 or 4

m∠2 = (x^2)° = (5^2)° or (4^2)°

m∠2 = 16° or 25°

7 0

2 years ago

A farmer is planning how to divide his land for planting next year’s crops. A triangular plot of land is left with two known sid

jeka57 [31]

He can either measure the third side length, apply the Pythagorean theorem to find the height of the triangle, and then calculate the area, or he can find the measure of the included angle between the known side lengths and use trigonometry to express the height of the triangle and then determine the

area of the triangle

7 0

2 years ago

Haley is twice as old as Riley. The sum of their ages is 39. Write an equation that represents (x) , Riley's age.

kenny6666 [7]

Answer:

X=39×2. Answer: 39×2= 78

6 0

2 years ago

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