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Greeley [361]
4 years ago
9

A chemist has a sample of hydrated Li2SiF6 and it weighs 0.4813 grams. He heats it strongly to drive off the water of hydration,

and after heating, he found that the anhydrous compound has a mass of 0.391 grams. What is the percent of water in the hydrate?
Chemistry
2 answers:
Aleksandr-060686 [28]4 years ago
6 0

Answer:

percentage of water = 18.76%

Explanation:

A chemist has a sample of hydrated Li2SiF6  and it weighs 0.4813 grams.

The overall weight of the compound is 0.4813 grams.

weight of hydrated sample = 0.4813 grams.

weight of anhydrous compound = 0.391 grams

percentage weight of water = mass of water/mass of the hydrated compound × 100

mass of water = mass of hydrated compound - mass of anhydrous compound

mass of water = 0.4813 - 0.391  = 0.0903 grams.

percentage of water = 0.0903/0.4813 × 100

percentage of water = 9.03/0.4813

percentage of water = 18.761687097

percentage of water = 18.76%

Sergeeva-Olga [200]4 years ago
5 0

Answer:

18.8%

Explanation:

Step 1:

The following data were obtained from the question.

Mass of hydrated Li2SiF6 = 0.4813 g

Mass of anhydrous Li2SiF6 = 0.391 g

Step 2:

Determination of the mass of the water in the hydrate.

Mass of water = (Mass of hydrated Li2SiF6) - (Mass of anhydrous Li2SiF6)

Mass of water = 0.4813 - 0.391

Mass of water = 0.0903 g

Step 3:

Determination of the percentage of water in the hydrate.

The percentage of water = Mass of water/ mass of hydrate x 100

The percentage of water = 0.0903/0.4813 x 100

The percentage of water = 18.8%

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3 years ago
In order to gain one pound of body weight, the average person must consume 3500 more calories
Fed [463]

Answer:

<em>17500 calories</em> of chocolate bars are needed to eat to gain 5 pounds.

Explanation:

We can use ratios to calculate the answer using the information given in the question.

1 pound : 3500 grams

5 pounds : x grams

As it is given that the individual is burning no calories, we do not have to factor in any additional numbers.

<u><em>Method</em><em> </em><em>A</em><em>:</em></u>

To go from 1 in the first ratio to 5 in the second ratio, they multipled 1 by 5. Hence, to go from 3500 in the first ratio to x in the second ratio, we must multiply by 5.

x = 3500 × 5

x = 17500

<em><u>Method B</u>:</em>

To solve for the answer x, we can convert the ratios into fractions.

1 / 5 = 3500 / x

3500 / x = 1 / 5

To make x the subject, multiply the denominator of the left fraction with the numerator of the right fraction and place it on the left side. Then multiply the numerator of the left fraction with the denominator of the right fraction and place it on the right side.

x = 5 × 3500

x = 17500

4 0
4 years ago
What is the name of this molecular compound ? F6I5 PLEASE AND THANK YOU
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Answer:

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Explanation:

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5 0
3 years ago
A stock solution of sodium sulfate NaSO4 has a concentrate of 1.00 m. The volume of this solution is 50 ml. What volume of 0.25
mylen [45]
<h3>Answer:</h3>

200 mL

<h3>Explanation:</h3>

Concept tested: Dilution formula

We are given;

  • Concentration of stock solution as 1.00 M
  • Volume of the stock solution as 50 mL
  • Molarity of the dilute solution as 0.25 M

We are required to calculate the volume of diluted solution;

  • The stock solution is the original solution before dilution while diluted solution is the solution after dilution.
  • Using the dilution formula we can determine the volume of diluted solution;

M1V1 = M2V2

Rearranging the formula;

V2 = M1V1 ÷ M2

     = (1.00 M × 50 mL) ÷ 0.25 M

     = 200 mL

Therefore, a volume of 200mL of 0.25 M solution could be made from the stock solution.

5 0
4 years ago
If you have 5 moles of carbon dioxide at 30degrees C and under 600mmHg of pressure, what will the volume be
trapecia [35]

Answer:

157.64 L

Explanation:

We'll begin by converting 30 °C to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

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T(K) = 30 °C + 273

T (K) = 303 K

Next, we shall convert 600 mmHg to atm. This can be obtained as follow:

760 mmHg = 1 atm

Therefore,

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600 mmHg = 0.789 atm

Finally, we shall determine the volume of the gas. This can be obtained as follow:

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Pressure (P) = 0.789 atm

Gas constant (R) = 0.0821 atm.L/Kmol

Volume (V) =?

PV = nRT

0.789 × V = 5 × 0.0821 × 303

0.789 × V = 124.3815

Divide both side by 0.789

V = 124.3815 / 0.789

V = 157.64 L

Therefore, the volume of the gas is 157.64 L

7 0
3 years ago
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