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natulia [17]
4 years ago
13

I have to obtain an empirical formula from:

Chemistry
1 answer:
JulsSmile [24]4 years ago
7 0
When finding empirical formulas decimals are fine so you wouldn't have to multiply all of them to turn into whole numbers. What you would do is divide each of those numbers by the smallest of those numbers and take the nearest whole number so if you had:

1.81 mol     .6 mol     and .3.61 mol you would divide each of those numbers by .6
and you would have 3, 1, and 6

for your problem you would divide them all by 1 and Carbon would be 2 (if your teacher normally has you round down at .5's then it would be 1)  hydrogen would be 3 and oxygen would be 1. 
C2H3O

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Please give brainliest it’s needed :(
5 0
4 years ago
1. An aqueous solution was prepared by mixing 70 g of an unknown nondissociating solute into 100 g of water. The solution has a
VladimirAG [237]

Answer:

The molar mass of the solute is 322.9 g/mol

Explanation:

Boiling point elevation to solve this:

ΔT = Kb . m

ΔT = T° boiling of solution - T°boiling of pure solvent

Kb → Ebullioscopic constant, for water is 0.512°C / m

m → molality

101.11°C - 100°C = 0.512 °C/m . m

1.11°C / 0.512 m/°C = m

2.17 = m → These are the moles of solute in 1kg of solvent

1kg = 1000 g. Let's make the rule of three to determine the moles in our solvent volume:

In 1000 g we have 2.17 moles of solute

In 100 g we may have (100 . 2.17)/1000 = 0.217 moles

The moles we obtained, are the moles for 70 g of mass.

Let's determine the molar mass: (g/mol)

70 g/ 0.217 mol = 322.9 g/mol

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3 years ago
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<u>Answer:</u> The product formed in the solution is PbCl_2(s)

<u>Explanation:</u>

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By Stoichiometry of the reaction:

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Hence, the product formed in the solution is PbCl_2(s)

5 0
3 years ago
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