The answer to yo question is ( it has three OH groups).
This solute-solvent interaction will release energy into the surroundings and makes the beaker warm.
<u>Explanation:</u>
The sulfuric acid is dissolved in water and it formed a solvation sphere of water molecules around the sulphur ions. So on stirring the beaker is getting warm. As the beaker is getting warm, this means the reaction occuring between sulfuric acid and water is exothermic reaction.
And so the energy is released into the surroundings. The energy released came from the breaking of bonds of sulfuric acid, as the acid is getting dissociated in water.
So, the release of energy in the surroundings lead to the warming of the beaker. Hence, the solute-solvent interaction release energy into the surroundings.
Explanation:
Hydrogen (H)
Helium (He)
Lithium (Li)
Beryllium (Be)
Boron (B)
Carbon (C)
Nitrogen (N)
Oxygen (O)
Fluorine (F)
Neon (Ne)
Sodium (Na)
Magnesium (Mg)
Aluminum (Al)
Silicon (Si)
Phosphorus (P)
Sulfur (S)
Chlorine (Cl)
Argon (Ar)
Potassium (K)
Calcium (Ca)
Hope this is correct and helpful
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Answer:
remove product
Explanation:
Removing the product will always shift the equilibrium to the right. This is based on the Le Chatelier's principle which states that "if any of the conditions of a system in equilibrium is changed, the system will adjust itself in order to annul the effect of the change".
- If a system at equilibrium is disturbed, by changing the concentration of one of the substances all the concentrations will change until a new equilibrium point is reached.
- Removing the product will increase the concentration of the species on the left hand side, the equilibrium will shift to the right.
D.) the original components retain their individual properties
