A beaker contains a dilute sodium chloride solution at 1 atmosphere. What happens to the number of solute particles in the solut
1 answer:
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Answer:
0.22M
Explanation:
We will be using the law of dilutions. We are simply increasing the amount of solvent to create a larger volume of solution.
So: moles before dilution = moles after dilution & . And M = moles/liter of solution, so if we express this as moles = M x
.
That is how we derive the formula we will be using:
or
Applying this formula to our problem, we can substitute the variables with the given values to find the molarity of the dilute solution.
M1 = 3.5M
V1 = 18.8mL
M2 = ?
V2 = 296.6mL
Equation: (3.5M)(18.8mL) = (296.6mL)(M2)
==> 65.8M*mL = 296.6mL * M2
==> M2 = (65.8 M*mL)/296.6mL
==> M2 = 0.22M
16 g/ml
<h3>Further explanation</h3>Given
mass = 32.40 g
volume = 2.0mL
Required
Density
Solution
Density is a quantity derived from the mass and volume
Density is the ratio of mass per unit volume
Density formula:
ρ = density
m = mass
v = volume
Input the value :
ρ = 32.40 g / 2.0 ml
ρ = 16.2 g/ml
Rules for division: The least number of significant figures in the problem determines the number of significant figures in the answer.
32.40 = 4 sig.fig
2.0 = 2 sig fig
The answer must be 2 sig fig
So the answer = 16 g/ml