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3 years ago

QUESTION 35

Physics

2 answers:

erastova [34]3 years ago

5 0

Answer:

C. The mattress decreases the man's force.

Explanation:

Has to be c

aliya0001 [1]3 years ago

5 0

Answer:

C. becuase this would make the man survive.

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Pls help

belka [17]

Answer:

2156 J

Explanation:

From the question,

Work done = Combined mass of the bucket and water×height×gravity.

W = (M+m)hg............................. Equation 1

Where M = mass of water, m = mass of the bucket, h = height, g = acceleration due to gravity.

Given: M = 20 kg, m = 2 kg, h = 10 m

Constant: g = 9.8 m/s²

Substitute these value into equation 1

W = (20+2)×10×9.8

W = 22×98

W = 2156 J

4 0

3 years ago

Two boxes are connected to each other as shown. The system is released from rest and the 1.00-kg box falls through a distance of

disa [49]

Answer:

The kinetic energy of box b is 2.44 J.

Explanation:

Given that,

Mass of box a =3.00 kg

Mass of box b=1.00 kg

Distance = 1.00 m

We need to calculate the acceleration of the system

Using formula of acceleration

$a=\dfrac{m_{2}\times g}{m_{1}+m_{2}}$

put the value into the formula

$a=\dfrac{1.00\times9.8}{1.00+3.00}$

$a=2.45\ m/s^2$

We need to calculate the velocity

Using equation of motion

$v^2=u^2+2as$

Put the value into the formula

$v^2=0+2\times2.45\times1.00$

$v=\sqrt{2\times2.45\times1.00}$

$v=2.21\ m/s$

We need to calculate the kinetic energy of box b

Using formula of energy

$K.E=\dfrac{1}{2}mv^2$

Put the value into the formula

$K.E=\dfrac{1}{2}\times1.00\times(2.21)^2$

$K.E=2.44\ J$

Hence, The kinetic energy of box b is 2.44 J.

3 0

4 years ago

Answer if you know the answer only.

borishaifa [10]

Answer:

4A*12Ω=48V

Explanation:

7 0

3 years ago

What is a density dependent limiting factor?

Sliva [168]

There are many types of density dependent limiting factors<span> such as:
1) Availability of food
2) Predation
3) Disease
4) Migration.

You should ask it in "Biology" instead of "Physics". Hope this helps!</span>

6 0

3 years ago

When a mass of 0.350 kg is attached to a vertical spring and lowered slowly, the spring stretches 0.120 m. The mass is now displ

AURORKA [14]

Answer:

Time period of the oscillation will be 0.695 sec

Explanation:

We have given mass attached to the string m = 0.350 kg

The spring is stretched by 0.120 m

So x = 0.120 m

We know that force is given by F = Kx

So mg = kx

$0.350\times 9.8=k\times 0.120$

k = 28.5833

Now time period is given by

$T=2\pi \sqrt{\frac{m}{k}}=2\times 3.14\sqrt{\frac{0.35}{28.5833}}=0.695sec$

So time period of the oscillation will be 0.695 sec

6 0

3 years ago