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Valentin [98]
3 years ago
10

Given the indices of refraction and of material 1 and material 2, respectively, rank these scenarios on the basis of the phase s

hift in the refracted ray. (n1 air=1.00 n2 water=1.33) (n1air=1.00 n2 quartz=1.46) (n1 water=1.33 n2 air=1.00) (n1 water=1.33 n2 dimond=2.42) (n1 benzen= 1.50 n2 water=1.33) (n1 water=1.33 n2quartz=1.46)
Physics
1 answer:
Over [174]3 years ago
7 0

Answer:

Explanation:    

when light travels from a more dense medium to a less dense medium the light ray is refracted (bent away) from the normal, where as when light travels from a less dense medium to a more dense medium, the light ray is refracted ( bent towards) the normal.

given that the phase shift in the refracted ray is  ∅

hence for Scenario 1 : air to water as against air to quartz

∅ for air to water would be greater than ∅ for air to quartz has quartz(1.46) is more dense than water (1.33)

Scenario 2 : water to air and water to diamond

∅ for water to air would be greater than ∅ for water to diamond as diamond (2.42) is more dense than air (1.0)

Scenario 3 : Benzene to Water and water to Quartz

∅ for Benzene to water would be greater than for ∅ for water to quartz as the light ray is travelling from a more dense medium to a less dense medium in benzene and water and hence it bends away from the normal, while the light ray is traveling from less dense to more dense medium in water and quartz and hence it bends towards the normal.

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A monatomic ideal gas in equilibrium at a pressure of 3 kPa and a temperature of 300 K is initially confined in a volume of 1.3
GuDViN [60]

To solve this problem, it is necessary to apply the concepts related to the change of entropy in function of the Volume in two states due to the number of moles and the ideal gas constant, this can be expressed as

\Delta S = nRln(\frac{V_2}{V_1})

Where,

R = Gas constant

V = Volume (at each state)

At the same time the number of moles of gas would be determined by the ideal gas equation, that is,

n = \frac{PV}{RT}

Where,

P = Pressure

V = Volume

R = Gas Constant

T = Temperature

n = \frac{(1000Pa)(1.3m^3)}{(300K)(8.314Pa\cdot m^3\cdot K^{-1}\cdot mol^{-1})}

n = 0.521mol

Using the value of moles to replace it in the first equation we have

\Delta S = (0.521mol)(8.314Pa\cdot m^3\cdot K^{-1}\cdot mol^{-1})ln(\frac{10.3m^3}{1.3m^3})

\Delta S = 9.01J/K

Therefore the correct option is A.

7 0
4 years ago
Can an electron be diffracted? Can it exhibit interference?
Serggg [28]

Answer:

Yeah, it can be diffracted. Though it depends on a diffracting medium.

It must have some magnetic fields .

Forexample; X-ray diffraction where electrons are diffracted to the target filament.

5 0
3 years ago
Explain two scenarios where a large truck can have the same momentum as a small car.
KengaRu [80]

The momentum, p, of any object having mass m and the velocity v is

p=mv\cdots(i)

Let M_L and M_S be the masses of the large truck and the car respectively, and V_L and V_S be the velocities of the large truck and the car respectively.

So, by using equation (i),

the momentum of the large truck = M_LV_L

and the momentum of the small car = M_SV_S.

If the large truck has the same momentum as a small car, then the condition is

M_LV_L=M_SV_S\cdots(ii)

The equation (ii) can be rearranged as

\frac {M_L}{M_S}=\frac {V_S}{V_L} \; or \; \frac{M_L}{V_S}=\frac{M_S}{V_L}

So, the first scenario:

\frac {M_L}{M_S}=\frac {V_S}{V_L}

\Rhghtarrow M_L:M_S=V_S:V_L

So, to have the same momentum, the ratio of mass of truck to the mass of the car must be equal to the ratio of velocity of the car to the velocity of the truck.

The other scenario:

\frac{M_L}{V_S}=\frac{M_S}{V_L}

\Rhghtarrow M_L:V_S= M_S:V_L

So, to have the same momentum, the ratio of mass of truck to the velocity of the car must be equal to the ratio of mass of the car to the velocity of the truck.

5 0
3 years ago
A giant log float on a lake while a tiny grain of sand sinks to the bathroom. Explain why a heavy object like the log floats whi
ella [17]

Answer:

Because the log is hollow or is less dense

Explanation:

If a log has little density, it will float. While sand is dense and completely solid, so it will sink.

7 0
3 years ago
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What is the cooling power P? Recall that the rate at which energy is removed, also called the cooling power, was described earli
gayaneshka [121]

Answer:

36.667

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(2.2*10^4)/(10*60)

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