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Lady_Fox [76]
2 years ago
15

A ball is thrown straight up with an initial speed of 12 m/s. What are the velocity and acceleration when it is at the top of it

s trajectory
Physics
1 answer:
Lesechka [4]2 years ago
8 0

Answer:

'A ball is thrown straight up with an initial speed of 12 m/s_ What are the velocity and acceleration when it is at the top of its trajectory? Select all apply. v=12 mls a = 0 v =-12 mls a = 9.8 m/s2 Oa=-9.8 m/s2'

Explanation:

I look it up

Hope this helps

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A satellite omass1000 kg moves in a circular orbit of radius 8000 km round the earth,assumed to be a sphere of radius 6400 km. C
lubasha [3.4K]

Answer:

ΔE = 37.8 x 10^9 J

Explanation:

The energy required will increased the potential energy and increase the kinetic energy.

As the altitude change is fairly small compared to the earth radius, we can ASSUME that the average gravity will be a good representative

Gravity acceleration at altitude would be 9.8(6400²/8000²) = 6.272 m/s²

G(avg) = (9.8 + 6.272)/2 = 8.036 m/s²

ΔPE = mG(avg)Δh = 1000(8.036)(8e6 - 6.4e6) = 12.857e9 J

The centripetal force at orbit must be equal to the gravity force

mv²/R = mg'

v²/8.0e6 = 6.272

v² = (6.272(8.0e6)) = 50.2e6 m²/s²

The maximum velocity when resting on earth at the equator is about 460 m/s.

The change in kinetic energy is

ΔKE = ½m(vf² - vi²)(1000)

ΔKE = ½(1000)(50.2e6 - 460²) = 25e9 J

Total energy increase is

25e9 + 12.857e9 = 37.8e9 J

3 0
2 years ago
Which of the following can sometimes be zero for a moving body i average velocity ii distance travelled iii average speed iv dis
Anika [276]

Answer:

<h3>displacement can be zero...because it only care about initial and final positions</h3>

3 0
3 years ago
A box is pulled to the right with a force of 65 n at an angle of 58 degrees to the horizontal the surface of frictional is the F
umka21 [38]

Answer:

The force acting in x direction is 34.44 N

Explanation:

We have,

Force acting on the box is 65 N at an angle of 58 degrees to the horizontal the surface of frictional.

It is required to find the net force in x- direction.

The net force acting in the x- direction is given by :

F_x=F\cos\theta\\\\F_x=65\times \cos(58)\\\\F_x=34.44\ N

So, the force acting in x direction is 34.44 N.

4 0
3 years ago
If an object weighs 40N, calculate the mass (gravity = 9.8m/s^2)​
Elan Coil [88]

Answer:

4.08 kg

Explanation:

We can apply the Newton's second law of motion to find the mass of this object:

F=ma,

where m is mass, and a is acceleration, which is substituted by g here. Now, plugging given numbers in the equation, we have

40=m\cdot9.8.

Solving for mass, we have

m=\frac{40}{9.8}\\=4.08 \;\text{kg}.

4 0
3 years ago
An MRI technician moves his hand from a region of very low (B=0) magnetic field strength into an MRI scanner’s 3.50 T field with
sattari [20]

Answer:

The change in the magnetic flux in the ring is 10.99 Wb.

Explanation:

Given that,

An MRI technician moves his hand from a region of very low (B=0) magnetic field strength into an MRI scanner’s 3.50 T field with his fingers pointing in the direction of the field.

Diameter of the ring, d = 2 cm

Radius, r = 1 cm

It takes 0.4 s to move it into the field. We need to find the change in magnetic flux in the ring. Magnetic flux is given by :

\phi=BA\\\\\phi=B\pi r^2\\\\\phi=3.5\pi \times (1)^2\\\\\phi=10.99\ Wb

So, the change in the magnetic flux in the ring is 10.99 Wb. Hence, this is the required solution.

4 0
3 years ago
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