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4 years ago

What are the differences between speed, velocity, and acceleration?

Physics

2 answers:

Levart [38]4 years ago

8 0

Answer:

speed is scaler quantity and velocity or acceleration is a vector quantity

irakobra [83]4 years ago

5 0

Answer:

Speed is a measure of how far something moves in a given amount of time.

Velocity is speed in a specific direction

Acceleration is the rate of change of velocity per unit of time.

Have a great day!

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NEED ANSWER ASAP what are the factors that affect the strength of a frictional force?

ololo11 [35]

It's not the second one since color has nothing to do with force. Also the third one isn't a factor since buoyant forces is the upward force of caused by fluid that opposes the object entering the liquid. The acceleration of the object and the mass of an object and how rough the surface are the only two factors in all the options.

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4 years ago

You illuminate a slit with a width of 71.7 μm with a light of wavelength 737 nm and observe the resulting diffraction pattern on

miskamm [114]

To solve this problem we will apply the concepts related to the double slit-experiment. Under this concept we understand the relationship between the minimum angle, depending on the order of the fringes, the wavelength and the distance between slits. Therefore we have the following relation,

$sin(\theta_{min}) = \frac{m\lambda}{D}$

Here,

m = Order of the fringes

D = Distance between slits

$\lambda$ = Wavelength

Replacing with our values we have,

$sin(\theta_{min}) = \frac{(1)(737*10^{-9})}{71.7*10^{-6}m}$

$sin(\theta_{min}) = 0.01028$

Through the relationship between distances then we have that the basic amplification distance is given by the relationship between the distance of the slit L and the angle, then

$Y=Lsin\theta$

$Y =2.27*0.01028$

$Y =0.0233m$

Thus the width of the central maximum is

$W=2Y=2*0.0233$

$W = 0.0466m$

Therefore the widht is 0.466m

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4 years ago

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Lapatulllka [165]

Answer:

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3 years ago

In this week's experiment, you send an unpolarized light beam through two polarizers in series. You orient the first polarizer s

g100num [7]

Answer:

Part a)

$\theta = 90 degree$

so the polarization axis of two polarizers must be at 90 degree

Part b)

$\theta = 20 + 14.3 = 34.3 degree$

(vi) set the second polarizer so that its angular scale reads 34.3 degrees.

Explanation:

Part 1)

As per law of Malus we know that the intensity of light coming from the second polarizer and the intensity of the light from first polarizer is related as

$I = I_o cos^2\theta$

now we know that we rotate the second polarizer till the intensity of the light becomes zero

so we will have

$I = 0$

so we will have

$\theta = 90 degree$

so the polarization axis of two polarizers must be at 90 degree

Part b)

when two axis are inclined at 90 degree then scale reads 104.3 degree

so here the scale exceeds the reading by

$\Delta \theta = 104.3 - 90 = 14.3$

so in order to make them inclined at 20 degree we will have

$\theta = 20 + 14.3 = 34.3 degree$

(vi) set the second polarizer so that its angular scale reads 34.3 degrees.

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4 years ago

Compare the three types of friction

Dominik [7]

The what i don't understand lol

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4 years ago