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anzhelika [568]

3 years ago

13

Edward runs with a speed of 3m/s. How long would it take him to run 2km? Give your answer in seconds to four significant figures

.

1 answer:

Whitepunk [10]3 years ago

5 0

Answer:

666.6 seconds

Explanation:

if he runs at 3m/sec he will achieve the goal of 2000m in 666.6 seconds. just divide - 3/2000.

note we have changed 2km to 2000metres

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What is the electric flux ΦΦPhi through each of the six faces of the cube?

BlackZzzverrR [31]

Flux through each of the six faces of the cube: $\frac{q}{6\epsilon_0}$

Explanation:

In this problem, a charge $q$ is placed at the center of the cube.

We can apply Gauss Law, which states that the flux through the surface of the cube is equal to the charge contained within the cube divided by the vacuum permittivity; mathematically:

$\Phi_T=\frac{q}{\epsilon_0}$

where

$q$ is the charge

$\epsilon_0$ is the vacuum permittivity

Here we want to find the flux through each of the six faces of the cube.

By simmetry, we can say that the 6 faces are identical: therefore, the flux through each of them must be the same. This means that the flux through each faces is 1/6 of the total flux through the total surface, therefore:

$\Phi = \frac{1}{6}\Phi = \frac{q}{6\epsilon_0}$

Learn more about electric fields:

brainly.com/question/8960054

brainly.com/question/4273177

#LearnwithBrainly

8 0

3 years ago

A charge Q is transferred from an initially uncharged plastic ball to an identical ball 24 cm away.The force of attraction is th

xxMikexx [17]

Answer:

The number of electrons transferred from one ball to the other is 2.06 x 10¹² electrons

Explanation:

Given;

magnitude of the attractive force, F = 17 mN = 0.017 N

distance between the two objects, r = 24 cm = 0.24 m

The attractive force is given by Coulomb's law;

$F = \frac{1}{4\pi \epsilon _0} \times \frac{Q^2}{r^2} = \frac{kQ^2}{r^2} \\\\Q^2 = \frac{Fr^2}{k} \\\\Q = \sqrt{ \frac{Fr^2}{k}} \\\\Q = \sqrt{ \frac{(0.017)(0.24)^2}{9\times 10^9}} \\\\Q = 3.298 \times 10^{-7} \ C$

The charge of 1 electron = 1.602 x 10⁻¹⁹ C

n(1.602 x 10⁻¹⁹ C) = 3.298 x 10⁻⁷

$n = \frac{3.298 \times 10^{-7}}{1.602 \times 10^{-19}} = 2.06 \times 10^{12} \ electrons$

Therefore, the number of electrons transferred from one ball to the other is 2.06 x 10¹² electrons

4 0

3 years ago

An ant walks 2\,\text m2m2, start text, m, end text to the right and then climbs 1 \,\text m1m1, start text, m, end text up a wa

NNADVOKAT [17]

Answer:

26.56°

Explanation:

given,

horizontal distance travel by the ant = 2 m

vertical distance travel by the ant = 1 m

angle of the ant above the initial point = ?

using trigonometric function

$tan \theta = \dfrac{h}{x}$

θ is the angle of the ant form initial position

h is the height on the wall

x is the horizontal distance covered by the ant

$tan \theta = \dfrac{1}{2}$

$\theta =tan^{-1}(0.5)$

$\theta =26.56^0$

hence, the angle made by the ant from the initial position is equal to 26.56°

3 0

3 years ago

marta [7]

Answer:

Let, R be the resistance of the heater wire. Since, two heater wires are of equal length their resistance is also same.

Hence, for series combination of resistances,

R

s

=2R

And for parallel combination of resistances,

R

p

=

2

R

Now, heat produced when they first connected in series is

H

s

=

R

s

V

2

where, V is voltage supplied to the heater.

H

s

=

2R

V

2

.....................................(1)

heat produced when they first connected in series is

H

p

=

R

p

V

2

H

p

=

2

R

V

2

H

p

=

R

2V

2

............................................(2)

From (1) and (2), we get

H

p

H

s

=

R

2V

2

2R

V

2

⇒

H

p

H

s

=

4

1

7 0

3 years ago

What is the weight of a 75kg. Mass?

AysviL [449]

W=(75kg)(9.8m/s^2

W = 735N

7 0

3 years ago

Read 2 more answers