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Nostrana [21]
3 years ago
15

4. Johnny exerts a 3.55 N rightward force on a 0.200-kg box to accelerate it across a low-friction track. If the total resistanc

e force to the motion of the cart is 0.52 N, then a) What is the box's acceleration? b) What is the gravitational force? c) What is the normal force?
Physics
1 answer:
muminat3 years ago
6 0

a) 15.2 m/s^2

b) 1.96 N

c) 1.96 N

Explanation:

a)

To find the acceleration of the box, we apply Newton's second law of motion:

\sum F=ma

where

\sum F is the net force on the box

m is the mass of the box

a is its acceleration

Here we have to consider the horizontal direction, which is the one in which the box is moving. The net force is given by:

\sum F=3.55 N - 0.52 N=3.03 N

which is the difference between the forward force and the resistive force. Then we have

m = 0.200 kg (mass of the box)

Therefore, the acceleration of the box is:

a=\frac{\sum F}{m}=\frac{3.03}{0.200}=15.2 m/s^2

b)

The gravitational force (also called weight) is the force with which an object is pulled by the Earth towards the Earth's centre.

It is given by

F_g = mg

where

m is the mass of the object

g is the acceleration due to gravity

In this problem, we have:

m = 0.200 kg is the mass of the box

g=9.8 m/s^2 is the acceleration due to gravity

Therefore, the gravitational force on the box is:

F_g=(0.200)(9.8)=1.96 N

c)

The normal force is the force with which a surface pushes back on an object.

For an object lying on a flat surface, there are two forces acting along the vertical direction:

- The gravitational force, F_g, which pushes the object downward

- The normal force, N, which pushes the object upward

As the object is at rest, the vertical acceleration of the object is zero, therefore according to Newton's second law of motion, the net force must be zero:

\sum F=F_g-N=0

Which means that the normal force is equal to the gravitational force:

N=F_g

And so, for the box in this problem, the normal force is

N=1.96 N

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A train rolls past a stationary observer. To him, the train is moving at a speed of 23m/s west, and a woman on the train is movi
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Answer:

21.7 seconds.

Explanation:

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To find how long she will take to move 13m relative to the train, take the distance she wants to travel divided by her velocity relative to the train.

(13m)/(0.6 m/s) = 21.6667 seconds or 21.7 seconds.  

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10. John has borrowed his parents car without permission and is driving without a license. He
Natasha2012 [34]
Yes

Explanation:
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I divided 500 by 25 to see how long it would take for John to get to his house
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4 0
3 years ago
.How long it will take to<br> travel 12m with the speed of<br> 330m/s
avanturin [10]

Answer:

0.036 seconds

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6 0
2 years ago
A specimen of aluminum having a rectangular cross section 9.5 mm × 13.0 mm (0.3740 in. × 0.5118 in.) is pulled in tension with 3
miskamm [114]

Answer: 〖4.1x10〗^(-3)

Explanation:

From the question, the parameters given are:

  • Force= 35600N(8003lbf)

  • Cross section (area)= 9.5mm x 13mm= 123.5 〖mm〗^2 = 0.0001235m^2 (after converting from 〖mm〗^2 to m^2 which is the standard unit for measuring length)

  • Modulus of elasticity = 69 GPa = 69 x 〖10〗^9 N/m^2

We can solve this using the formula for elastic modulus ( E ) = stress/strain  

making strain the subject of the formula the equation above becomes strain= stress/ elastic modulus

Where strain= change in length/ length

And  

Stress= force/ area

now let’s calculate value for stress

Stress= 35600/0.0001235=288,259,109  N/m^2

substituting the value for stress into the equation strain= stress/ elastic modulus we have

Strain= 288,259,109 / 69 x 〖10〗^9 = 〖4.1x10〗^(-3)

7 0
3 years ago
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