Answer:
a) The schematic illustrating is attached
b) The heat transfer to the heat engine is 2142.86 kJ, the heat transfer from the heat engine is 1392.86 kJ
c) The heat transfer to the heat engine is 1648.35 kJ, the heat transfer from the heat engine is 898.35 kJ
Explanation:
b) The heat transfer to the engine and the heat transfer from the engine to the air is:
Where
W = 750 kJ
n = 35% = 0.25
Replacing:
c) The efficiency of Carnot engine is:
The heat transfer to the heat engine is:
The heat transfer from the heat engine is:
The astronomers introduced the most widely accepted hypothesis regarding the origin of the solar system is Immanuel Kant in 1755.
Newton's equations of gravity and rotatory motion served as the foundation for most of Kant's theories. He believed that primaeval matter, which he believed to have been generated supernaturally, was dispersed throughout the cosmos. Small, chilly, hard particles made up this substance.
Due to the gravitational pull of one another, these particles were drawn to one another.
In his 1755 "The Universal Natural History and Views of the Heavens," Kant discusses astronomy as well as two significant cosmological theories. The first is his "Nebular Hypothesis" on the formation of stars and planets, in which he proposed that faint, thin clouds of dust and gas far out in space would collapse in on themselves under the influence of gravity, forcing them to spin to form a disc. The development of stars and planets from this rotating disc would account for the rotation of Earth and the other planets.
To learn more about Nebular Hypothesis refer the link:
brainly.com/question/27986174
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In 1 hour, the hour hand sweeps across 1/12 of the clock's face. In 40 min, the hour hand travels (40 min)/(60 min) = 2/3 of the path it covers in an hour, so a total of 1/12 × 2/3 = 1/18 of the clock's face. This hand traces out a circle with radius 0.25 m, so in 40 min its tip traces out 1/18 of this circle's radius, or
1/18 × 2<em>π</em> (0.25 m) ≈ 0.087 m
The minute hand traverses (40 min)/(60 min) = 2/3 of the clock's face, so it traces out 2/3 of the circumference of a circle with radius 0.31 m:
2/3 × 2<em>π</em> (0.31 m) ≈ 1.3 m
The second hand completes 1 revolution each minute, so in 40 min it would fully trace the circumference of a circle with radius 0.34 m a total of 40 times, so it covers a distance of
40 × 2<em>π</em> (0.34 m) ≈ 85 m
