We have that the speed of a body covering a distance of 320 km in 4h is mathematically given as
V=22.22m/s is
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From the question we are told
calculate the speed of a body covering a distance of 320 km in 4h
Generally the equation for the Speed is mathematically given as
V=22.22m/s
Hence
The speed of a body covering a distance of 320 km in 4h is
V=22.22m/s
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1.Paper Chromatography. This method is often used in the food industry. ...
2.Filtration. This is a more common method of separating an insoluble solid from a liquid. ...
3.Evaporation. ...
4Simple distillation. ...
Fractional distillation.
Answer:
P = 17.28*10⁶ N
Explanation:
Given
L = 250 mm = 0.25 m
a = 0.54 m
b = 0.40 m
E = 95 GPa = 95*10⁹ Pa
σmax = 80 MPa = 80*10⁶ Pa
ΔL = 0.12%*L = 0.0012*0.25 m = 3*10⁻⁴ m
We get A as follows:
A = a*b = (0.54 m)*(0.40 m) = 0.216 m²
then, we apply the formula
ΔL = P*L/(A*E) ⇒ P = ΔL*A*E/L
⇒ P = (3*10⁻⁴ m)*(0.216 m²)*(95*10⁹ Pa)/(0.25 m)
⇒ P = 24624000 N = 24.624*10⁶ N
Now we can use the equation
σ = P/A
⇒ σ = (24624000 N)/(0.216 m²) = 114000000 Pa = 114 MPa > 80 MPa
So σ > σmax we use σmax
⇒ P = σmax*A = (80*10⁶ Pa)*(0.216 m²) = 17280000 N = 17.28*10⁶ N
1N=1kg•m/s^2 so the answer is 3N
Answer:
The minimum speed required is 5.7395km/s.
Explanation:
To escape earth, the kinetic energy of the asteroid must be greater or equal to its gravitational potential energy:
or
where 
is the mass of the asteroid, 
is its distance form earth's center, 
is the mass of the earth, and 
is the gravitational constant.
Solving for 
we get:
putting in numerical values gives
in kilometers this is
Hence, the minimum speed required is 5.7395km/s.
