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jek_recluse [69]
3 years ago
12

que ventajas e inconvenientes tienen las energias renovables, el agua del mar, agua embalzada, el sol, el viento

Physics
1 answer:
ahrayia [7]3 years ago
5 0

Answer:

Ventajas ambientales:

La principal ventaja es la prácticamente es nula la emisión de gases de efecto invernadero (GEI).

* Ayudan a disminuir enfermedades relacionadas con la contaminación.

* No necesitan grandes cantidades de agua para su funcionamiento.

* No crean problemas de basura difíciles de resolver, como la eliminación de residuos nucleares o escorias.

Ventajas económicas:

*Generación de empleos directos (trabajadores de la construcción, desarrolladores, fabricantes de equipo, diseñadores, instaladores, financieros).

* Competencia y reducción de precios de las generadoras tradicionales por tener un nuevo competidor, que asegure confiabilidad del servicio.

ENERGÍA SOLAR INCONVENIENTES:

La instalación de paneles solares en casas o industrias no es barato, además no todas las vivienda pueden instalarse este tipo de paneles. La legislación en cuanto al uso de los paneles solares no es la misma en todo el mundo.

ENERGÍA EÓLICA INCONVENIENTES:

La creación de parques eólicos es muy cara, además hay colectivos que se opinen a la instalación de parques eólicos en tierra porque opinan que afea el paisaje y es peligrosos para las aves que chocan al volar cerca de las hélices de los generadores eólicos.

ENERGÍA DE LAS MAREAS INCONVENIENTES:

El movimiento de las mareas mueve las turbinas. El movimiento de las mareas es capaz de mover turbinas, pero para ello hay que construir represas o aluviones.

Entre los inconvenientes está que la construcción de aluviones es muy cara. Hay oposición de grupos ecologistas que destacan que esta energía puede tener un impacto negativo sobre la fauna acuática. La energía de las mareas puede reducir el flujo de las mareas e impedir el flujo de aguas residuales al mar.

Explanation:

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Find the resistance of wire of<br>0.65m Radius 0.25<br>and<br>resistivity 3x10-6 OHM<br>​
densk [106]

Complete Question:

Find the resistance of a wire of length 0.65 m, radius 0.25 mm and resistivity 3 * 10^{-6} ohm-metre.

Answer:

Resistance = 9.95 Ohms

Explanation:

<u>Given the following data;</u>

Length = 0.65 m

Radius = 0.25 mm to meters = 0.00025 m

Resistivity = 3 * 10^{-6} ohm-metre.

To find the resistance of the wire;

Mathematically, resistance is given by the formula;

Resistance = P \frac {L}{A}

Where;

  • P is the resistivity of the material.
  • L is the length of the material.
  • A is the cross-sectional area of the material.

First of all, we would find the cross-sectional area of the wire.

Area of circle = πr²

Substituting into the equation, we have;

Area  = 3.142 * (0.00025)²

Area = 3.142 * 6.25 * 10^{-8}

Area = 1.96 * 10^{-7} m²

Now, to find the resistance of the wire;

Resistance = 3 * 10^{-6} * \frac {0.65}{1.96 * 10^{-7}}

Resistance = 3 * 10^{-6} * 3316326.531

<em>Resistance = 9.95 Ohms </em>

5 0
3 years ago
The average radius of Mars is 3,397 km. If Mars completes one rotation in 24.6 hours, what is the tangential speed of objects on
sammy [17]

Answer: First, we determine the circumference of the Mars by the equation below.  

                                     C = 2πr

Substituting the known values,

                                     C = 2(π)(3,397 km) = 6794π km

To determine the tangential speed, we divide the circumference calculated above by the time it takes for Mars to complete one rotation and that is,

                   tangential speed = 6794π km / 24.6 hours = 867.64 km/h

6 0
3 years ago
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A rock is thrown down from the top of a cliff with a velocity of 3.61 m/s (down). The cliff is 28.4 m above the ground. Determin
Katarina [22]
I’m not sure look it up in the internet!
4 0
3 years ago
Determine the CM of a rod assuming its linear mass density λ (its mass per unit length) varies linearly from λ = λ0 at the left
Dahasolnce [82]

Answer:

x_c= \dfrac{5}{9}L

I=\dfrac {7}{12}\lambda_ 0 L^3

Explanation:

Here mass density of rod is varying so we have to use the concept of integration to find mass and location of center of mass.

At any  distance x from point A mass density

\lambda =\lambda_0+ \dfrac{2\lambda _o-\lambda _o}{L}x

\lambda =\lambda_0+ \dfrac{\lambda _o}{L}x

Lets take element mass at distance x

dm =λ dx

mass moment of inertia

dI=\lambda x^2dx

So total moment of inertia

I=\int_{0}^{L}\lambda x^2dx

By putting the values

I=\int_{0}^{L}\lambda_ ox+ \dfrac{\lambda _o}{L}x^3 dx

By integrating above we can find that

I=\dfrac {7}{12}\lambda_ 0 L^3

Now to find location of center mass

x_c = \dfrac{\int xdm}{dm}

x_c = \dfrac{\int_{0}^{L} \lambda_ 0(1+\dfrac{x}{L})xdx}{\int_{0}^{L} \lambda_0(1+\dfrac{x}{L})}

Now by integrating the above

x_c=\dfrac{\dfrac{L^2}{2}+\dfrac{L^3}{3L}}{L+\dfrac{L^2}{2L}}

x_c= \dfrac{5}{9}L

So mass moment of inertia I=\dfrac {7}{12}\lambda_ 0 L^3 and location of center of mass  x_c= \dfrac{5}{9}L

8 0
3 years ago
Which bond(s) shown are double bonds?
Nikitich [7]

Answer:

I'm pretty sure its the 2nd one.

3 0
3 years ago
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