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jek_recluse [69]
3 years ago
12

que ventajas e inconvenientes tienen las energias renovables, el agua del mar, agua embalzada, el sol, el viento

Physics
1 answer:
ahrayia [7]3 years ago
5 0

Answer:

Ventajas ambientales:

La principal ventaja es la prácticamente es nula la emisión de gases de efecto invernadero (GEI).

* Ayudan a disminuir enfermedades relacionadas con la contaminación.

* No necesitan grandes cantidades de agua para su funcionamiento.

* No crean problemas de basura difíciles de resolver, como la eliminación de residuos nucleares o escorias.

Ventajas económicas:

*Generación de empleos directos (trabajadores de la construcción, desarrolladores, fabricantes de equipo, diseñadores, instaladores, financieros).

* Competencia y reducción de precios de las generadoras tradicionales por tener un nuevo competidor, que asegure confiabilidad del servicio.

ENERGÍA SOLAR INCONVENIENTES:

La instalación de paneles solares en casas o industrias no es barato, además no todas las vivienda pueden instalarse este tipo de paneles. La legislación en cuanto al uso de los paneles solares no es la misma en todo el mundo.

ENERGÍA EÓLICA INCONVENIENTES:

La creación de parques eólicos es muy cara, además hay colectivos que se opinen a la instalación de parques eólicos en tierra porque opinan que afea el paisaje y es peligrosos para las aves que chocan al volar cerca de las hélices de los generadores eólicos.

ENERGÍA DE LAS MAREAS INCONVENIENTES:

El movimiento de las mareas mueve las turbinas. El movimiento de las mareas es capaz de mover turbinas, pero para ello hay que construir represas o aluviones.

Entre los inconvenientes está que la construcción de aluviones es muy cara. Hay oposición de grupos ecologistas que destacan que esta energía puede tener un impacto negativo sobre la fauna acuática. La energía de las mareas puede reducir el flujo de las mareas e impedir el flujo de aguas residuales al mar.

Explanation:

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vladimir2022 [97]

Answer:

golf all on grass covered hill in sunlight

Explanation:

someone pouring/spinning top has a lot of motion going on. a roller coaster has force acting on it which increases the motion.

3 0
3 years ago
Read 2 more answers
A beam of red light is made to pass through two slits that are 3.55 E-3 meters apart. On a screen 2.25 meters away from the slit
JulsSmile [24]
I am assuming you know the relation obtained between slit width, distance of screen from slits, distance of interference pattern obtained on the screen from the center and the wavelength of monochromatic light used in Young's Double Slit experiment.
λ =\frac{y*d}{D} =  \frac{3.55*10^{-3}*1.25*10^{-4}  }{2.25} = 1.97*10^{-7} m
λ ~ 1.97 ×10⁻⁷m
7 0
3 years ago
A uniform disk, a thin hoop, and a uniform sphere, all with the same mass and same outer radius, are each free to rotate about a
olga nikolaevna [1]

Answer:

4 hoop, disk, sphere

Explanation:

Because

We are given data that

Hoop, disk, sphere have Same mass and radius

So let

And Initial angular velocity, = 0

The Force on each be F

And Time = t

Also let

Radius of each = r

So let's find the inertia shall we!!

I1 = m r² /2

= 0.5 mr² the his is for dis

I2 = m r² for hoop

And

Moment of inertia of sphere wiil be

I3 = (2/5) mr²

= 0.4 mr²

So

ωf = ωi + α t

= 0 + ( τ / I ) t

= ( F r / I ) t

So we can see that

ωf is inversely proportional to moment of inertia.

And so we take the

Order of I ( least to greatest ) :

I3 (sphere) , I1 (disk) , I2 (hoop) , ,

Order of ωf: ( least to greatest)

That of omega xf is the reverse of inertial so

hoop, disk, sphere

Option - 4

5 0
3 years ago
Light of wavelength 560 nm passes through a slit of width 0. 170 mm. (a) the width of the central maximum on a screen is 8. 00 m
faltersainse [42]

The distance between slit and the screen is 1.214m.

To find the answer, we have to know about the width of the central maximum.

<h3>How to find the distance between slit and the screen?</h3>
  • It is given that, wavelength 560 nm passes through a slit of width 0. 170 mm, and the width of the central maximum on a screen is 8. 00 mm.
  • We have the expression for slit width w as,

                           w=\frac{2*wavelength*d}{a}

where, d is the distance between slit and the screen, and a is the slit width.

  • Thus, distance between slit and the screen is,

                           d=\frac{w*a}{2*wavelength} =\frac{8*10^{-3}*0.17*10^{-3}}{560*10^{-9}*2} \\\\d=1.214m

Thus, we can conclude that, the distance between slit and the screen is 1.214m.

Learn more about the width of the central maximum here:

brainly.com/question/13088191

#SPJ4

3 0
2 years ago
Can y’all please help me quickkkkk just give me answers it wouldn’t even take a minute from ur life pleaseee
shusha [124]

There's only one question there.

The answer is "Greater amplitude".

6 0
3 years ago
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