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11Alexandr11 [23.1K]
4 years ago
6

Does a jerboa use its short front feet and long back legs to dig a burrow

Physics
1 answer:
Korvikt [17]4 years ago
6 0
It uses its back legs
You might be interested in
Technician a says that that both slip rings must be insulated from the rotor shaft. technician b says that at least one slip rin
trasher [3.6K]

Answer:

Technician A is correct while Technician B is incorrect.

Explanation:

If Technician a says that that both slip rings must be insulated from the rotor shaft, then, technician a is correct.

If technician b says that at least one slip ring must be grounded to the shaft to provide a complete circuit for current flow, this statement is incorrect because each slip ring must be connected to one of the three phases of rotor windings. And the slip ring brushes are connected to a resistive device ( like a rheostat). When the slip rings turn with the rotor, the brushes will maintain constant contact with the rings and transfer the resistance to the rotor windings. Therefore, Technician A is correct while Technician B is incorrect.

5 0
3 years ago
To test the performance of its tires, a car travels along a perfectly flat (no banking) circular track of radius 130 m. The car
marysya [2.9K]

Answer:

0.739

Explanation:

If we treat the four tire as single body then

W ( weight of the tyre ) =  mass × acceleration due to gravity (g)

the body has a tangential acceleration = dv/dt = 5.22 m/s², also the body has centripetal acceleration to the center = v² / r

where v is speed 25.6 m/s and r is the radius of the circle

centripetal acceleration = (25.6 m/s)² / 130 = 5.041 m/s²

net acceleration of the body = √ (tangential acceleration² + centripetal acceleration²) = √ (5.22² + 5.041²) = 7.2567 m/s²

coefficient of static friction between the tires and the road = frictional force / force of normal

frictional force = m × net acceleration / m×g

where force of normal = weight of the body in opposite direction

coefficient of static friction = (7.2567 × m) / (9.81 × m)

coefficient of static friction = 0.739

4 0
3 years ago
1. What is the speed of a wave with wavelength 2.5m and frequency 20Hz?
Korvikt [17]

Answer:

50m/s

Explanation:

v = f*w

3 0
3 years ago
Read 2 more answers
How is desert pavement formed?
mihalych1998 [28]

Desert pavement or commonly called stone or stony pavement is a type of desert surface that is covered with pebbles and stone tight and intertwined. Many of these layers form a type of pavement known as mosaic. When the particles begin to be stacked between different natural agents such as rain, gravity and animals compact the layers and generates a layer that allows the pavement not to erode. Basically runoff and deflation eliminate silt and clay, leaving thicker particles behind.

The correct answer is A.

5 0
3 years ago
If we have a velocity of 20 m/s and our acceleration is -5 m/s, then after 2 seconds our velocity will be....
svetoff [14.1K]

Answer:

v = 10 m/s

Explanation:

We have,

Our initial velocity is 20 m/s

Our acceleration, a=-5\ m/s^2

It is required to find the velocity after 2 seconds. It is a concept based on equation of kinematics. Using first equation:

v=u+at

Plugging all the known values

v=20+(-5)(2)\\\\v=10\ m/s

So, our final velocity is 10 m/s.

6 0
4 years ago
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