Remember that since energy is conserved, the kinetic energy it takes to jump to a height of 1.2 m is just the same as the potential energy difference between ground level and the 1.2 m height.
Potential energy = (mass)(gravity)(height) = (7.2 kg)(9.81 m/s^2)(1.2 m) = 84.76 J
Therefore, the kinetic energy required for the dog to jump to a 1.2-m height is 84.76 Joules.
Answer:
B. 102,900 N
I remember this question from one of my, test. Really hope this helps..
= 454.55 g/cm3
I'm not too sure since the graduated cylinder was missing and I really don't know how to do it then. But give this a shot. Are you sure it wasn't a graduated cylinder, because I have no idea what that means
The acceleration of the particle at time t is:
![a(t)=24t^2 ft/s^2](https://tex.z-dn.net/?f=a%28t%29%3D24t%5E2%20ft%2Fs%5E2)
The velocity of the particle at time t is given by the integral of the acceleration a(t):
![v(t)= \int a(t) \, dt = \int (24 t^2) dt=24 \frac{t^3}{3}=8t^3 ft/s](https://tex.z-dn.net/?f=v%28t%29%3D%20%5Cint%20a%28t%29%20%5C%2C%20dt%20%3D%20%5Cint%20%2824%20t%5E2%29%20dt%3D24%20%5Cfrac%7Bt%5E3%7D%7B3%7D%3D8t%5E3%20ft%2Fs%20)
and the position of the particle at time t is given by the integral of the velocity v(t):
![x(t)=\int v(t) = \int (8t^3)=8 \frac{t^4}{4}=2t^4 ft](https://tex.z-dn.net/?f=x%28t%29%3D%5Cint%20v%28t%29%20%3D%20%5Cint%20%288t%5E3%29%3D8%20%20%5Cfrac%7Bt%5E4%7D%7B4%7D%3D2t%5E4%20ft%20)
Assuming the particle starts from position x(0)=0 at t=0, the distance the particle covers in the first t=2 seconds can be found by substituting t=2 s in the equation of x(t):
Answer:
The definitive and unifying theme or idea of a story or article. It encompasses all the aspects necessary to create a coherent main idea. The central idea is typically expressed as a universal truth or theme that is built and supported by the setting and characters in a story.
Explanation:
This is the correct answer to your question.
Hope this helps!!!
Kyle.