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Answer:
The value of capillary rise in the tube = 0.0363 cm
Explanation:
Diameter of the glass tube = 0.03 meter
Contact angle = 22 degree
We know that the capillary rise (h) in the tube is given by the formula =
h = (2 α cos β) / (d g R )
⇒ d = density of gasoline = 749 kg / 
β = 22 degree
R = radius of the tube = 0.015 m
α = surface tension of gasoline = 0.0216 N / m
cos 22 = 0.927
Put all the values in the above formula we get
⇒ h = (2 × 0.0216 × 0.927) / (749 × 9.81 × 0.015)
⇒ h = 0.0363 cm
This is the value of capillary rise in the tube.
Answer:
12.5 ft/s
Explanation:
Height of person = 6 ft
height of lamp post = 10 ft
According to the question,
dx / dt = 5 ft/s
Let the rate of tip of the shadow moves away is dy/dt.
According to the diagram
10 / y = 6 / (y - x)
10 y - 10 x = 6 y
y = 2.5 x
Differentiate both sides with respect to t.
dy / dt = 2.5 dx / dt
dy / dt = 2.5 (5) = 12.5 ft /s
Answer:
8.4335 x 10^-²¹, 1.78204 x 10²⁶
Explanation:
p = mv
p = (5.05 x 10⁶)(1.67 x 10^-²⁷)
p = 8.4335 x 10^-²¹
p = mv
p = (5.98 x 10²⁴)(2.98 x 10)
p = 1.78204 x 10²⁶