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Alexandra [31]
3 years ago
12

1. What is the speed of a wave with wavelength 2.5m and frequency 20Hz?

Physics
2 answers:
Korvikt [17]3 years ago
3 0

Answer:

50m/s

Explanation:

v = f*w

neonofarm [45]3 years ago
3 0

Answer:

50 ans..

Explanation:

Data :

v = ?

wavelength= 2.5 m

f = 20 Hz

Formula:

<em>s</em><em>p</em><em>e</em><em>e</em><em>d</em><em> </em><em>=</em><em> </em><em>(</em><em>f</em><em>r</em><em>e</em><em>q</em><em>u</em><em>e</em><em>n</em><em>c</em><em>y</em><em> </em><em>)</em><em>(</em><em>w</em><em>a</em><em>v</em><em>e</em><em>l</em><em>e</em><em>n</em><em>g</em><em>t</em><em>h</em><em>)</em><em> </em>

Solution:

v = ( 20 )( 2.5 )

v = 50 metre per second <em>A</em><em>n</em><em>s</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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A skier starts from rest at the top of a hill that is inclined 10.5° with respect to the horizontal. The hillside is 200 m long,
Svetlanka [38]

Answer:

d) 289.31 m

Explanation:

Energy provided by potential energy = mgh = m x 9.8x 200 sin10.5 = 357.18m

Energy used by friction = μmgcos 10.5 x 200 = .075 x m x 9.8 x cos 10.5 x200 = 144.54 m .

Energy used by friction on plain surface = μmg x d.( dis distance covered on plain ) =.075x m x 9.8 xd = .735 m d

To equate

357.18 m -144.54 m = .735 m d

d = 289.31 m .

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3 years ago
The mini-refrigerator fire was most likely caused by what type of wiring?
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Answer: The copper wiring most likely caused the mini-refrigerator fire.

Explanation: A mini-refrigerator may have one or more evaporator fan motors. These motors have copper wiring. In some situation these copper wires gets overheated. It may result to the firing of the mini-refrigerator.

Therefore, the mini-refrigerator fire was most likely caused by copper wiring.

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A 1400 kg car is traveling east on the highway at 31 m/s and collides into the rear of a slower moving pickup truck of 2400 kg,
zloy xaker [14]

Answer: 31 m/s due east

Explanation: this question can be solved using the law of conservation of linear momentum.

This law states that in a closed or isolated system, during collision, the vector sum of momentum before collision equals the vector sum of momentum after collision.

Momentum = mass × velocity

From our question, our parameters before collision are given below as

Mass of car = mc = 1400kg

Speed of car =vc = 31 m/s (due east)

Mass of truck = mt = 2400kg

Velocity of truck = vt = 25 m/s ( due east )

After collision

Velocity of car = ?

Velocity of truck = 34 m/s ( due east )

Vector sum of momentum before collision is given as

1400 (31) + 2400 (25) = 43400 + 60000 = 103400 kgm/s

After collision the truck is seen to move faster (v = 34 m/s) which implies that the car also moves due east .

1400 (v) + 2400(25) .... A positive value is between both momenta because they are in the same direction.

After collision, we have that

1400v + 60000

Vector sum of momentum before collision = vector sum of momentum after collision

103400 = 1400v + 60000

103400 - 60000 = 1400v

43400 = 1400v

v = 43400/ 1400

v = 31 m/s due east

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