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Alexandra [31]
3 years ago
12

1. What is the speed of a wave with wavelength 2.5m and frequency 20Hz?

Physics
2 answers:
Korvikt [17]3 years ago
3 0

Answer:

50m/s

Explanation:

v = f*w

neonofarm [45]3 years ago
3 0

Answer:

50 ans..

Explanation:

Data :

v = ?

wavelength= 2.5 m

f = 20 Hz

Formula:

<em>s</em><em>p</em><em>e</em><em>e</em><em>d</em><em> </em><em>=</em><em> </em><em>(</em><em>f</em><em>r</em><em>e</em><em>q</em><em>u</em><em>e</em><em>n</em><em>c</em><em>y</em><em> </em><em>)</em><em>(</em><em>w</em><em>a</em><em>v</em><em>e</em><em>l</em><em>e</em><em>n</em><em>g</em><em>t</em><em>h</em><em>)</em><em> </em>

Solution:

v = ( 20 )( 2.5 )

v = 50 metre per second <em>A</em><em>n</em><em>s</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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A spaceprobe has an 29.0 m length when measured at rest. What length
elixir [45]

Answer:

The observer sees the space-probe 9.055m long.

Explanation:

Let L_0 be the length of the space-probe when measured at rest, and L be its length as observed by an observer moving at velocity v, then

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Now, we know that L_0 = 29.0m and v = 0.95c, and putting these into (1) we get:

L = 29\sqrt{1-\dfrac{(0.95c)^2}{c^2} }

L = 29\sqrt{1-0.95^2 }

\boxed{L = 9.055m}

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3 years ago
A refrigeration cycle has Qout = 1000 Btu and Wcycle = 300 Btu. Determine the coefficient of performance for the cycle.
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Answer:

The coefficient of performance for the cycle is 2.33.

Explanation:

Given that,

Output energy Q_{out}=1000\ Btu

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COP=\dftrac{Q_{in}}{W_{cycle}}

We need to calculate the Q_{in}

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Put the value into the formula

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Now put the value of Q_{in} into the formula of COP

COP=\dfrac{700}{300}

COP=\dfrac{7}{3}=2.33

Hence, The coefficient of performance for the cycle is 2.33.

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