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Alexandra [31]
3 years ago
12

1. What is the speed of a wave with wavelength 2.5m and frequency 20Hz?

Physics
2 answers:
Korvikt [17]3 years ago
3 0

Answer:

50m/s

Explanation:

v = f*w

neonofarm [45]3 years ago
3 0

Answer:

50 ans..

Explanation:

Data :

v = ?

wavelength= 2.5 m

f = 20 Hz

Formula:

<em>s</em><em>p</em><em>e</em><em>e</em><em>d</em><em> </em><em>=</em><em> </em><em>(</em><em>f</em><em>r</em><em>e</em><em>q</em><em>u</em><em>e</em><em>n</em><em>c</em><em>y</em><em> </em><em>)</em><em>(</em><em>w</em><em>a</em><em>v</em><em>e</em><em>l</em><em>e</em><em>n</em><em>g</em><em>t</em><em>h</em><em>)</em><em> </em>

Solution:

v = ( 20 )( 2.5 )

v = 50 metre per second <em>A</em><em>n</em><em>s</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em><em>.</em>

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8 0
3 years ago
A 10kg box accelerates forward at a rate of 12 m/s^2. What is the force acting on the box?
Allushta [10]

Answer:

120N

Explanation:

Newton's second law formula: F= ma

given that m = 10 kg, a = 12 m/s^2

F = ma = 10 kg * 12 m/s^2 = 120 kgm/s^2 = 120 N

5 0
2 years ago
2×3.14√(1.0m/(9.8〖ms〗^(-1) )=)
il63 [147K]

This is the period in a simple harmonic motion which is 2 seconds in this question.

<h3>What is Period ?</h3>

The period of an oscillatory object can be defined as the total time taken  by a vibrating body to make one complete revolution about a reference point.

We are given the below question

2×3.14√(1.0m/(9.8〖ms〗^(2) )= T

This question can as well be expressed as

2π√(L/g) which is equal to period T.

In a nut shell, Period T = 2×3.14√(1.0m/9.8)

T = 6.28√0.102

T = 6.28 × 0.32

T = 2.006 s

Therefore, the period T of the oscillation is 2 seconds approximately.

Learn more about Period here: brainly.com/question/12588483

#SPJ1

8 0
1 year ago
After landing on an unfamiliar planet, a space explorer constructs a simple pendulum of length 49.0 cm . The explorer finds that
iren2701 [21]

Answer: g = 10.0 m/s/s

Explanation:

For a simple pendulum, provided that the angle between the lowest and highest point of  his trajectory be small, the oscillation period is given by the following expression:

T = 2π √L/g , where L = pendulum length, g= accelleration of gravity.

We can also define the period, as the time needed to complete a full swing, so from the measured  values, we can conclude the following :

T = 140 sec/ 101 cycles = 1.39 sec

Equating both definitions for T, we can solve for g, as follows:

g = 4 π² L / T² = 4π². 0.49 m / (1.39)² = 10.0 m/s/s

7 0
3 years ago
The speed of sound through air is approximately 340 m/sec. What is the wavelength of a sound wave with a frequency of 706 Hz? Ro
cestrela7 [59]

Answer:

Wavelength  = 0.48 m (Approx)

Explanation:

Given:

Speed of sound = 340 m/s

Frequency = 706 hz

Find:

Wavelength

Computation:

Wavelength  = Speed of sound / Frequency

Wavelength  = 340 / 706

Wavelength  = 0.48 m (Approx)

7 0
2 years ago
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