The efficiency of the engine at the given useful energy and input energy is 28%.
The given parameters:
- <em>Input energy of the engine, = 125 J</em>
- <em>Useful energy of the engine, 35 J</em>
The efficiency of the engine is defined as the ratio of the output energy (useful energy) to the input energy and it is calculated as follows;
Thus, the efficiency of the engine at the given useful energy and input energy is 28%.
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Answer:
Explanation:
Energy is defined as the ability to cause changes in matter. The energy of moving matter is called kinetic energy.
Answer:
Hope this helps you find the answer
Explanation:
Chemical Digestion of Carbohydrates, Proteins, Lipids, and Nucleic Acids. The chemical breakdown of the macromolecules contained in food is completed by various enzymes produced in the digestive system.
Answer:
First calculate the deceleration making use of the formulation: V(very last speed= U(initial speed) -a(acceleration) t(ime) so 10=20- 4a. unfavourable a as decelerating. making a the acceleration the challenge by using rearranging the elements 4a= 20-10 = 10 so a=10/4 making use of Newton's 2d regulation P(stress) = M (mass) x A (acceleration). so P = 800 x 10/4 = 8000 /4 = 2000 newtons
Explanation:
I think your best bet would be.
It acts in the direction opposite of the motion
