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laiz [17]
3 years ago
6

A sound wave traveling through dry air has a frequency of 15 Hz, a

Physics
2 answers:
Korolek [52]3 years ago
3 0

Answer:

Option B

Explanation:

Speed of a wave is denoted by:

v=fλ

where f is the frequency which is unchanged 15Hz and λ is the new wavelength which is 28m

v=fλ

v=15(28)\\v=420m/s

adell [148]3 years ago
3 0

Answer: b. 420 m/s

Explanation: ap3x

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Why is it that an object can accelerate while
posledela

For the same reason that you can skate around a curve at constant speed but not with constant velocity.

The DIRECTION you're going is part of your velocity, but it's not part of your speed.

If the DIRECTION changes, that's a change of velocity.

The object doesn't have to change speed to have a different velocity. A change of direction is enough to do it.

And any change of velocity is called acceleration.

3 0
3 years ago
E asteroid belt circles the sun between the orbits of mars and jupiter. one asteroid has a period of 6.0 earth years. part a wha
anzhelika [568]

To solve the problem, use Kepler's 3rd law : 

T² = 4π²r³ / GM 

Solved for r : 

r = [GMT² / 4π²]⅓ 

but first covert 6.00 years to seconds : 

6.00years = 6.00years(365days/year)(24.0hours/day)(6... 
= 1.89 x 10^8s 

The radius of the orbit then is : 

r = [(6.67 x 10^-11N∙m²/kg²)(1.99 x 10^30kg)(1.89 x 10^8s)² / 4π²]⅓ 
= 6.23 x 10^11m

6 0
3 years ago
Two children are riding on a merry-go-round that is rotating with a constant angular speed. Abbie is one meter from the center o
klio [65]

Answer:

The acceleration of Abbie is half of the Zak's.

Explanation:

The centripetal acceleration of an object on a circular path is given by :

a=r\omega^2

Two children are riding on a merry-go-round that is rotating with a constant angular speed. Let r_1 is distance of Abbie from the merry-go-round and r_2 is distance of Zak's from the merry-go-round. Acceleration of Abbie is :

a_1=r_1\omega^2 ...... (1)

r_1=1\ m

Acceleration of Zak's is :

a_2=r_2\omega^2 .......(2)

r_2=2\ m

Dividing equation (1) and (2) we get :

\dfrac{a_1}{a_2}=\dfrac{r_1}{r_2}\\\\\dfrac{a_1}{a_2}=\dfrac{1}{2}\\\\a_1=\dfrac{a_2}{2}

So, the acceleration of Abbie is half of the Zak's.

7 0
3 years ago
An object slides down a frictionless inclined plane. At the bottom, it has a speed of 9.80 m/s. What is the vertical height of t
Papessa [141]

The vertical height of the given plane is 4.9 m.

The given parameters:

  • <em>speed of the object at the bottom of the ramp, v = 9.8 m/s</em>

The vertical height of the plane is calculated by applying principle of conservation of mechanical energy as follows;

P.E = K.E\\\\mgh = \frac{1}{2} mv^2\\\\h = \frac{v^2}{2g} \\\\h = \frac{9.8 \times 9.8}{2 \times 9.8} \\\\h = 4.9 \ m

Thus, the vertical height of the given plane is 4.9 m.

Learn more about conservation of mechanical energy here: brainly.com/question/332163

7 0
3 years ago
when a metal sphere is dropped in to a tall cylinder containing liquid its acceleration is g÷2 (gravity over 2) show that : dens
Kryger [21]

The density of the metal sphere is 2 times the density of the liquid as proved.

<h3>Net upward force acting on the metal sphere</h3>

The net upward force acting on the sphere as it is dropped into the liquid is calculated as follows;

F =  σVg - ρVg

ma =  σVg - ρVg  

where;

  • ρ is density of the liquid
  • σ is the density of the metal
  • a is acceleration of the metal

σV(a) =  σVg  - ρVg

σ(a) = σg  - ρg

σ(g/2) = σg -  ρg  

g(σ/2) = g(σ -  ρ)

σ/2 = σ -  ρ

σ/2 - σ = -  ρ

-σ/2 = -  ρ

σ = 2ρ

Thus, the density of the metal sphere is 2 times the density of the liquid as proved.

Learn more about density here: brainly.com/question/1354972
#SPJ1

6 0
2 years ago
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