It is a wedge because of the ramp thingy
Answer:
one step UVU i dont even know XD there is no picture or graph?
Explanation:
Answer:
the volume of liquid decreased due to evaporation from the exposed free surface of water so molecules got evaporated .
evaporation occurs at room temperature.
She ran for 3s
Put 18/6 because in order to find how long she ran for you need to divide the distance by the meters ran, once you do that you will get 3.
The kinetic energy of the mass at the instant it passes back through its equilibrium position is about 1.20 J
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<h3>Further explanation</h3>
Let's recall Elastic Potential Energy formula as follows:
![\boxed{E_p = \frac{1}{2}k x^2}](https://tex.z-dn.net/?f=%5Cboxed%7BE_p%20%3D%20%5Cfrac%7B1%7D%7B2%7Dk%20x%5E2%7D)
where:
<em>Ep = elastic potential energy ( J )</em>
<em>k = spring constant ( N/m )</em>
<em>x = spring extension ( compression ) ( m )</em>
Let us now tackle the problem!
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<u>Given:</u>
mass of object = m = 1.25 kg
initial extension = x = 0.0275 m
final extension = x' = 0.0735 - 0.0275 = 0.0460 m
<u>Asked:</u>
kinetic energy = Ek = ?
<u>Solution:</u>
<em>Firstly , we will calculate the spring constant by using </em><em>Hooke's Law</em><em> as follows:</em>
![F = k x](https://tex.z-dn.net/?f=F%20%3D%20k%20x)
![mg = k x](https://tex.z-dn.net/?f=mg%20%3D%20k%20x)
![k = mg \div x](https://tex.z-dn.net/?f=k%20%3D%20mg%20%5Cdiv%20x)
![k = 1.25(9.8) \div 0.0275](https://tex.z-dn.net/?f=k%20%3D%201.25%289.8%29%20%5Cdiv%200.0275)
![k = 445 \frac{5}{11} \texttt{ N/m}](https://tex.z-dn.net/?f=k%20%3D%20445%20%5Cfrac%7B5%7D%7B11%7D%20%5Ctexttt%7B%20N%2Fm%7D)
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<em>Next , we will use </em><em>Conservation of Energy</em><em> formula to solve this problem:</em>
![Ep_1 + Ek_1 = Ep_2 + Ek_2](https://tex.z-dn.net/?f=Ep_1%20%2B%20Ek_1%20%3D%20Ep_2%20%2B%20Ek_2)
![\frac{1}{2}k (x')^2 + mgh + 0 = \frac{1}{2}k x^2 + Ek](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B2%7Dk%20%28x%27%29%5E2%20%2B%20mgh%20%2B%200%20%3D%20%5Cfrac%7B1%7D%7B2%7Dk%20x%5E2%20%2B%20Ek)
![Ek = \frac{1}{2}k (x')^2 + mgh - \frac{1}{2}k x^2](https://tex.z-dn.net/?f=Ek%20%3D%20%5Cfrac%7B1%7D%7B2%7Dk%20%28x%27%29%5E2%20%2B%20mgh%20-%20%5Cfrac%7B1%7D%7B2%7Dk%20x%5E2)
![Ek = \frac{1}{2}k ( (x')^2 - x^2 ) + mgh](https://tex.z-dn.net/?f=Ek%20%3D%20%5Cfrac%7B1%7D%7B2%7Dk%20%28%20%28x%27%29%5E2%20-%20x%5E2%20%29%20%2B%20mgh)
![Ek = \frac{1}{2}(445 \frac{5}{11}) ( 0.0460^2 - 0.0275^2 ) + 1.25(9.8)(0.0735)](https://tex.z-dn.net/?f=Ek%20%3D%20%5Cfrac%7B1%7D%7B2%7D%28445%20%5Cfrac%7B5%7D%7B11%7D%29%20%28%200.0460%5E2%20-%200.0275%5E2%20%29%20%2B%201.25%289.8%29%280.0735%29)
![\boxed {Ek \approx 1.20 \texttt{ J}}](https://tex.z-dn.net/?f=%5Cboxed%20%7BEk%20%5Capprox%201.20%20%5Ctexttt%7B%20J%7D%7D)
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<h3>Learn more</h3>
![\texttt{ }](https://tex.z-dn.net/?f=%5Ctexttt%7B%20%7D)
<h3>Answer details</h3>
Grade: High School
Subject: Physics
Chapter: Elasticity