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Alenkasestr [34]
3 years ago
6

Which type of energy in gasoline is transformed into mechanical energy in a motorcycle engine?

Physics
2 answers:
Alexeev081 [22]3 years ago
6 0

Answer:

Chemical energy into mechanical energy

Explanation:

In the motor cycle engine, a piston, compress the gasoline to higher pressure to the extent of creating a spark. when sparked the chemical energy stored in the bonds is released in the form of heat energy .

This heat energy then pushes piston down which is the work or mechanical energy

So the chemical energy in bonds are first converted into thermal energy and this thermal energy is converted into mechanical energy

avanturin [10]3 years ago
3 0
Chemical-->thermal (heat) and pressure as fuel burns--> mechanical as pressure pushes piston down
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A jeweler working with a heated 47 g gold ring must lower the ring's temperature to make it safe to handle. If the ring is initi
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Mass of gold m₁ = 47 g

Initial temperature of gold T₁ = 99 C

Specific heat of gold C₁ = 0.129 J/gC

final temperature T₂ = 38 C

Heat needed by the gold to cool down

Q =m₁ * C₁* ( T₁ - T₂)

Q = (47)(0.129)(99-38)

Q = 369.843 J

This heat will be given by the water

we need to find out mass of water m₂

and initial temperature of water is T₃ = 25 C

Specific heat of water C₂ = 4.184 J/gC

Q = m₂*C₂*(T₂ - T₃)

369.843 = m₂(4.184)(38-25)

m₂ = 6.8 g

6 0
3 years ago
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The power of a machine is 6000 W. This machine is scheduled for design improvements. Engineers have reduced the
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Explanation:

Work = power × time

W = (6000 W) (7.5 s)

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7 0
3 years ago
Which of the following is a<br> compound?<br> A. Sodium<br> B. Salt<br> C. Potassium<br> D. Argon
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B. Salt

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2 years ago
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Capacitor 2 has half the capacitance and twice the potential difference as capacitor 1. What is the ratio (U_{\rm C})_1/\,(U_{\r
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Answer:

1/2

Explanation:

The energy stored in a capacitor is given by

U=\frac{1}{2}CV^2

where

C is the capacitance

V is the potential difference

Calling C_1 the capacitance of capacitor 1 and V_1 its potential difference, the energy stored in capacitor 1 is

U=\frac{1}{2}C_1 V_1^2

For capacitor 2, we have:

- The capacitance is half that of capacitor 1: C_2 = \frac{C_1}{2}

- The voltage is twice the voltage of capacitor 1: V_2 = 2 V_1

so the energy stored in capacitor 2 is

U_2 = \frac{1}{2}C_2 V_2^2 = \frac{1}{2}\frac{C_1}{2}(2V_1)^2 = C_1 V_1^2

So the ratio between the two energies is

\frac{U_1}{U_2}=\frac{\frac{1}{2}C_1 V_1^2}{C_1 V_1^2}=\frac{1}{2}

4 0
3 years ago
When cars are equipped with flexible bumpers, they will bounce off each other during low-speed collisions, thus causing less dam
iris [78.8K]

Answer:

Explanation:

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U1 = 1.6 m/s

U2 = -1.1 m/s

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M2 = 1400 kg

V1 = 0.27 m/s

Using momentum- collision equation,

M1U1 + M2U2 = M1V1 + M2V2

1850 × 1.6 - 1400 × 1.1 = 1850 × 0.27 + 1400 × V2

1420 = 499.5 + 1400V2

V2 = 0.6575 m/s

B.

KE = 1/2 × MV^2

KEa1 + KEa2 = KEb1 + KEb2

Delta KE = KE2 - KE1

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KEb2 = 302.6 J

KE1 = KEa1 + KEb1

= 3215 J

KE2 = 370.033 J

Delta KE = -2845 J.

5 0
3 years ago
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