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3 years ago

Which type of energy in gasoline is transformed into mechanical energy in a motorcycle engine?

Physics

2 answers:

Alexeev081 [22]3 years ago

6 0

Answer:

Chemical energy into mechanical energy

Explanation:

In the motor cycle engine, a piston, compress the gasoline to higher pressure to the extent of creating a spark. when sparked the chemical energy stored in the bonds is released in the form of heat energy .

This heat energy then pushes piston down which is the work or mechanical energy

So the chemical energy in bonds are first converted into thermal energy and this thermal energy is converted into mechanical energy

avanturin [10]3 years ago

3 0

Chemical-->thermal (heat) and pressure as fuel burns--> mechanical as pressure pushes piston down

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On Earth, you can lift a 10 kg object. What is the mass of that object on the moon? Is mass independent from gravity?

attashe74 [19]

Explanation:

An object's weight depends on the pull of the gravitating object but the object'<u>s mass is independent of the gravity. </u>

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2 years ago

A dogsled team has a total momentum of 1710 kg•m/s. If the team has a total mass of 450 kg, what is its speed?

HACTEHA [7]

Answer:

3.8 m/s

Explanation:

Momentum is the product of mass and velocity hence

Momentum=mv where m is mass and v is the velocity of an object

Making v the subject of the formula then

$v=\frac {momentum}{m}$

Substituting 1710 kgm/s for momentum and 450 Kg for mass we obtain

$v=\frac {1710 Kgm/s}{450 Kg}=3.8 m/s$

Hence the speed of dogsled team is 3.8 m/s

7 0

3 years ago

Read 2 more answers

A block of mass m = 0.23 kg is set against a spring with a spring constant of k1 = 553 N/m which has been compressed by a distan

madreJ [45]

Answer:

$X_2 = 0.122m$

Explanation:

Using the law of the convervation of energy E:

$E_i = E_f$

so:

$\frac{1}{2}K_1X_1^2 = \frac{1}{2}K_2X_2^2$

where $K_1$ is the constant of the spring 1, $X_1$ the compressed of the first spring, $K_2$ is the constant of the second spring and $X_2$ is the compressed of the second spring.

Replacing values, we get:

$\frac{1}{2}(553N/m)(0.1m)^2 = \frac{1}{2}(370N/m)X_2^2$

Solving for $X_2$ :

$X_2 = 0.122m$

8 0

3 years ago

The sun currently rotates once every 24.47 days. The solar radius is 6.963x10^8 m. As the Sun ages it will evolve into a type of

Natalka [10]

Answer:

$T \approx 586468.163\,days$

Explanation:

The initial angular speed of the Sun is:

$\omega_{o} = \frac{2\pi}{(24.47\,days)\cdot \left(86400\,\frac{s}{days} \right)}$

$\omega_{o} \approx 2.972\times 10^{-6}\,\frac{rad}{s}$

Let suppose that Sun can be modelled as an uniform sphere, the moment of inertia is:

$I = \frac{2}{5}\cdot m \cdot r^{2}$

The initial moment of inertia is:

$I =\frac{2}{5}\cdot (1.989\times 10^{30}\,kg)\cdot (6.983\times 10^{8}\,m)^{2}$

$I = 3.879\times 10^{47}\,kg\cdot m^{2}$

The angular momentum is:

$L = (3.879\times 10^{47}\,kg\cdot m^{2})\cdot (2.972\times 10^{-6}\,\frac{rad}{s} )$

$L = 1.153\times 10^{42}\,kg\cdot \frac{m^{2}}{s}$

Given the absence of external forces exerted on the Sun, the final angular speed can found by the Principle of Angular Momentum Conservation. The final moment of inertia is:

$I =\frac{2}{5}\cdot (1.989\times 10^{30}\,kg)\cdot (1.081\times 10^{11}\,m)^{2}$