All categories

3 years ago

Which type of energy in gasoline is transformed into mechanical energy in a motorcycle engine?

Physics

2 answers:

Alexeev081 [22]3 years ago

6 0

Answer:

Chemical energy into mechanical energy

Explanation:

In the motor cycle engine, a piston, compress the gasoline to higher pressure to the extent of creating a spark. when sparked the chemical energy stored in the bonds is released in the form of heat energy .

This heat energy then pushes piston down which is the work or mechanical energy

So the chemical energy in bonds are first converted into thermal energy and this thermal energy is converted into mechanical energy

avanturin [10]3 years ago

3 0

Chemical-->thermal (heat) and pressure as fuel burns--> mechanical as pressure pushes piston down

You might be interested in

A bridge to be fabricated of steel girders is designed to be 500 m long and 12 m wide at ambient temperature (assumed 20°C). Exp

andrew-mc [135]

Answer:

21.7391304348 m

Explanation:

L = Initial length = 500 m

$\Delta T$ = Change in temperature = 40-(-35)

$\alpha$ = Coefficient of thermal expansion = $12\times 10^{-6}\ /^{\circ}C$

Change in length is given by

$\Delta L=L\alpha \Delta T\\\Rightarrow \Delta L=500\times 12\times 10^{-6}\times (40-(-35))\\\Rightarrow \Delta L=0.45\ m$

The change in length is 0.45 m

The number of joints would be

$n=\dfrac{0.45}{0.02}\\\Rightarrow n=22.5\\\Rightarrow n\approx 23$

The number of joints is 23

Each bridge section length would be

$\dfrac{L}{n}=\dfrac{500}{23}=21.7391304348\ m$

The length of each bridge section would be 21.7391304348 m

4 0

3 years ago

If the work done to stretch an ideal spring by 4.0 cm is 6.0J, what is the spring constant (force constant) of this spring?

cluponka [151]

As AL2006 correctly pointed out the formula is 1/2 kx^2. I was thinking of force and work is the integral of force over the distance applied. So now
$W= \frac{1}{2}k x^{2}$
and
$\frac{2*6.0}{0.04^{2} } = k =7500 \frac{J}{m^{2}}$

8 0

3 years ago

Read 2 more answers

If a car is taveling with a speed 6 and comes to a curve in a flat road with radius ???? 13.5 m, what is the minumum value the c

Lemur [1.5K]

Answer:

$\mu_s \geq 0.27$

Explanation:

The centripetal force acting on the car must be equal to mv²/R, where m is the mass of the car, v its speed and R the radius of the curve. Since the only force acting on the car that is in the direction of the center of the circle is the frictional force, we have by the Newton's Second Law:

$f_s=\frac{mv^{2}}{R}$

But we know that:

$f_s\leq \mu_s N$

And the normal force is given by the sum of the forces in the vertical direction:

$N-mg=0 \implies N=mg$

Finally, we have:

$f_s=\frac{mv^{2}}{R} \leq \mu_s mg\\\\\implies \mu_s\geq \frac{v^{2}}{gR} \\\\\mu_s\geq \frac{(6\frac{m}{s}) ^{2}}{(9.8\frac{m}{s^{2}})(13.5m) }\\\\\mu_s\geq0.27$

So, the minimum value for the coefficient of friction is 0.27.

4 0

3 years ago

How much net force is needed to accelerate a 20kg mass at 2.5 m/s2?

Ksenya-84 [330]

Answer:

$\boxed{Force \: needed = 50 \: N}$

Given:

Mass = 20 kg

Acceleration = 2.5 m/s²

Explanation:

Force = mass × acceleration

= 20 × 2.5

= 50 kg m/s² or 50 N

8 0

3 years ago

Describe what happens to the gravitational force between two objects when their masses are increased

Inessa [10]

Answer:

So as the mass of either object increases, the force of gravitational attraction between them also increases. If the mass of one of the objects is doubled, then the force of gravity between them is doubled. If the mass of one of the objects is tripled, then the force of gravity between them is tripled.

Explanation:

6 0

3 years ago