PLEASE HELP ME I JUST CAN'T FIGURE THIS ONE OUT

Physics

2 answers:

kupik [55]3 years ago

4 0

Indeed the answer is c!!

S_A_V [24]3 years ago

4 0

THE ANSWER IS C. :) :) :)

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A proton accelerates from rest in a uniform electric field of 680 N/C. At one later moment, its speed is 1.30 Mm/s (nonrelativis

Ksivusya [100]

Answer:

Acceleration, $a=6.51\times 10^{10}\ m/s^2$

Explanation:

Given that,

Electric field, E = 680 N/C

Speed of the proton, v = 1.3 Mm/s

We need to find the acceleration of the proton. We know that the force due to motion is balanced by the electric force as :

$qE=ma$

a and m are the acceleration and mass of the proton.

$a=\dfrac{qE}{m}$

$a=\dfrac{1.6\times 10^{-19}\times 680}{1.67\times 10^{-27}}$

$a=6.51\times 10^{10}\ m/s^2$

So, the acceleration of the proton is $a=6.51\times 10^{10}\ m/s^2$ . Hence, this is the required solution.

3 0

3 years ago

In a collision that is not perfectly elastic, what happens to the mechanical energy of the system?

joja [24]

C.

Thanks me later, that's my answer.

5 0

3 years ago

A 1.5 kg orange falls from a tree and hits the ground in 0.75s. What is the speed of the orange just before it hits the ground?

Olenka [21]

The final speed of the orange is 7.35 m/s

Explanation:

The motion of the orange is a free fall motion, since there is only the force of gravity acting on it. Therefore, it is a uniformly accelerated motion with constant acceleration $g=9.8 m/s^2$ towards the ground. So we can use the following suvat equation: