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aleksley [76]
3 years ago
13

How can we calculate the e.m.f of the battery?.

Physics
2 answers:
cluponka [151]3 years ago
7 0

Explanation:

The emf is equal to the work done on the charge per unit charge (ϵ=dWdq) when there is no current flowing. Since the unit for work is the joule and the unit for charge is the coulomb, the unit for emf is the volt (1V=1J/C).

Tems11 [23]3 years ago
6 0

Answer:

The EMF or electromotive force is the energy supplied by a battery or a cell per coulomb (Q) of charge passing through it. The magnitude of emf is equal to V (potential difference) across the cell terminals when there is no current flowing through the circuit. (byjus)

Explanation:

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Waves with a higher frequency have a ______ wavelength and _____ energy. *
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Answer:

bsdk........m.....MC...

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3 years ago
Is 51/17 a rational number
mylen [45]

Answer:

Yes.

Explanation:

51/17 is a rational number because "A number is considered a rational number if it can be written as one integer divided by another integer."

6 0
3 years ago
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A box with a mass of 50 kg is raised straight up. What is the force of the box?
8_murik_8 [283]

Answer:

A box with a mass of 50 kg is raised straight up. What is the force of the box? plss help!! two types exist-positive and negative. possible answers: A- electric current B- repel C- lines of force D- charges. Five wavelengths are generated every 0.100 s in a tank of water.

Explanation:

I hope it helped

3 0
2 years ago
The magnitude of the electrostatic force between two identical ions that are separated by a distance of 5.0A is 3.7×10^-9N.a) wh
jeyben [28]

Explanation:

Given that,

Electrostatic force, F=3.7\times 10^{-9}\ N

Distance, r=5\ A=5\times 10^{-10}\ m

(a) F=\dfrac{kq^2}{r^2}, q is the charge on the ion              

q=\sqrt{\dfrac{Fr^2}{k}}

q=\sqrt{\dfrac{3.7\times 10^{-9}\times (5\times 10^{-10})^2}{9\times 10^9}}      

q=3.2\times 10^{-19}\ C

(b) Let n is the number of electrons are missing from each ion. It can be calculated as :

n=\dfrac{q}{e}

n=\dfrac{3.2\times 10^{-19}}{1.6\times 10^{-19}}

n = 2

Hence, this is the required solution.                        

8 0
3 years ago
At the county fair, Chris throws a 0.12kg baseball at a 2.4kg wooden milk bottle, hoping to knock it off its stand and win a pri
viva [34]

Answer:

v_{f2} =6.5%v_{i1}

Explanation:

Mass of the ball: m_{1} =0.12kg]

Initial velocity of the ball:   v_{i1}

final velocity of the ball: v_{f1} which is -30/100 of v_{i1} =-0.3v_{i1}

Mass of the bottle: m_{2} =2.4kg

Initial velocity of the bottle: v_{i2}=0m/s

final velocity of the bottle: v_{f2} is unknown (to find)

<em>by using conservation momentum, which stated that the initial momentum is equal to the final momentum.</em>

<em />m_{1} v_{i1} +m_{2} v_{i2} =m_{1} v_{f1} +m_{2} v_{f2}<em />

<em>so since the bottle is at rest firstly, therefore </em>v_{i2} =0<em />

<em />m_{1} v_{i1} +m_{2} (0) =m_{1} v_{f1} +m_{2} v_{f2}<em />

<em />m_{1} v_{i1}  =m_{1} v_{f1} +m_{2} v_{f2}<em>         </em><em>equation 1</em>

so now substitute v_{f1} into equation 1

m_{1} v_{i1}  =m_{1} (-0.3v_{i1} ) +m_{2} v_{f2}

<em />m_{1} v_{i1}  = -0.3m_{1}v_{i1}  +m_{2} v_{f2}<em />

<em>collect the like terms</em>

m_{1} v_{i1}   +0.3m_{1}v_{i1}  =m_{2} v_{f2}

1.3m_{1} v_{i1}   =m_{2} v_{f2}

divide both  side by m_{2}

v_{f2}=\frac{1.3m_{1} v_{i1}}{m_{2} }

Now substitute

v_{f2} =\frac{1.3*0.12*v_{i1}}{2.4}\\v_{f2}    =\frac{0.156v_{i1} }{2.4} \\v_{f2} =0.065v_{i1}

v_{f2} =6.5%v_{i1}

<em />

6 0
3 years ago
Read 2 more answers
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