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aleksley [76]
3 years ago
13

How can we calculate the e.m.f of the battery?.

Physics
2 answers:
cluponka [151]3 years ago
7 0

Explanation:

The emf is equal to the work done on the charge per unit charge (ϵ=dWdq) when there is no current flowing. Since the unit for work is the joule and the unit for charge is the coulomb, the unit for emf is the volt (1V=1J/C).

Tems11 [23]3 years ago
6 0

Answer:

The EMF or electromotive force is the energy supplied by a battery or a cell per coulomb (Q) of charge passing through it. The magnitude of emf is equal to V (potential difference) across the cell terminals when there is no current flowing through the circuit. (byjus)

Explanation:

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A football coach sits on a sled while two of his players build their strength by dragging the sled across the field with ropes.
Jobisdone [24]

Answer:

F=507.7N

Explanation:

According to Newton's second law:

\sum F=m.a

in this case, the football players need to drag the coach at a constant velocity, thus means with no acceleration, so:

\sum F=0\\\\-F_f+F_p*cos(\theta)=0\\\\

there are 20 degrees between the two ropes that means each player exerts a force 10 degrees from the zero reference.

F_p=2*F\\\\F=\frac{1000N}{2*cos(10)}\\\\F=507.7N

5 0
3 years ago
How do you best describe hypothesis? A. a carefully researched answer
Kamila [148]

A hypothesis is a possible theory to how something might work. The answer is D.

3 0
3 years ago
An object of mass 300 kg is observed to accelerate at the rate of 4 m/s 2 . Calculate the force required to produce this acceler
Marianna [84]

Answer:

F = 1200 N

General Formulas and Concepts:

<u>Forces</u>

Newton's Second Law of Motion: F = ma

  • F is force (in N)
  • m is mass (in kg)
  • a is acceleration (in m/s²)

Explanation:

<u>Step 1: Define</u>

<em>Identify variables</em>

<em>m</em> = 300 kg

<em>a</em> = 4 m/s²

<u>Step 2: Find Force</u>

  1. Substitute in variables [Newton's Second Law of Motion]:                           F = (300 kg)(4 m/s²)
  2. Multiply:                                                                                                            F = 1200 N

Topic: AP Physics 1 - Algebra Based

Unit: Forces

6 0
2 years ago
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pav-90 [236]
The pointer of an analog meter is connected to a "<span>coil suspended by bearings"

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6 0
3 years ago
You are explaining to friends why astronauts feel weightless orbiting in the space shuttle, and they respond that they thought g
TiliK225 [7]

Answer:

Only 9% weaker

Explanation:

Because this is where most stuff that people do in space takes place. So, um, here we're at a radius of the earth plus 300 kilometers. You may already be seeing why this isn't going to have much effect if this were except the 6.68 times, 10 to the sixth meters. And so the value of Gout here. You know, Newton's gravitational constant times, the mass of the Earth divided by R squared for the location we're looking at. And so this works out to be 8.924 meters per second squared, which is certainly less than it is at the surface of the earth. However, this is only 9% less than acceleration for gravity at the surface. So the decrease in the gravity gravitational acceleration of nine percent not really going toe produces a sensation of weightlessness.

4 0
3 years ago
Read 2 more answers
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