F(x) = 1/(x+2) & g(x) = x/(x-3)
(f(x) + g(x) = 1/(x+2) + x/(x-3). Reduce to same denominator:
1/(x+2) + x/(x-3) =(x-3) + x(x-3)/(x+2).(x-3) ==> (x²+3x-3)/(x+2).(x-3)
Answer:
False i think
Step-by-step explanation:
Answer:
first check the smallest number that divide 784
i.e 2
784/2 = 392/2= 196/2 =98/2 =49/7=7
we get
748= 2*2*2*2*7*7
for square root take one out of 2 same number
square root of 784= 2*2*7 = 28
My guess is 30 mins sorry if wrong hope this helps
2(4y+1) = 3y. We need to solve for y.
First let's get ride of the parenthesis by developing 2(4y+1). This means to multiply 2 by 4y and 2 by 1, and add them.
2(4y+1) = 2*4y + 2*1 = 8y + 2
So 2(4y+1)=3y
8y+2 = 3y
Then you subtract 8y from each side to have the variables on a side and the numbers on the other:
3y - 8y = 8y + 2 - 8y
-5y = 2
Then you divide each side by -5 to get the variable y alone on a side and its value on the other:
(-5y)/-5 = 2/-5
y = -2/5
You can re-check your answer (very important):
2(4y + 1) = 2(4*-2/5 + 1) = -1.2
3y = 3 * -2/5 = -1.2
So 2(4y+1)=3y= -1.2
The answer has been approved.
Hope this Helps! :)