M= 1 and n = 2
( m+ n = 1 +2 = 3)
rate = K [A] [B]^2
0.2 = K * 3 * 3 ^2
0.2 = K * 3 * 9
K = 0.2 / 27
K = 7.408 * 10 ^ -3 m^-2 s^-1
Answer:
The superscript after the letter
tells us the electrons are in the n=2 energy level.
Explanation:
The a<span>tomic mass of helium is 4.002642g/mol </span>
<span>(542000g)/(4.002642g/mol)*6.02*10^23 = 8.15*10^28 atoms
If you don't understand comment, not everyone understands what the / and * mean ^.^</span>
<h2>Hello!</h2>
The answer is: C2H6
<h2>Why?</h2>
First, we need to find the empirical formula of the compound:
Looking for the relative atomic mass for each element:
Finding the number of moles for each element:
Then, we need to determinate the mole ratio by dividing each result into the smallest number:
So, the empirical formula would be CH3
We are given the molar mass of the compound is equal to 30 g/mol
We need to compare the empirical formula molecular mass and the molecular formula molar mass in order to find the number of atoms of the compound:
Empirical formula molar mass:
Molecular formula molar mass = 30.0 g/mol
So, by dividing the molecular formula molar mass by the empirical formula molar mass we have the number of atoms of the compound:
Therefore,
The molecular formula will be: (CH3)2= C2H6
Have a nice day!
Answer: The empirical formula for the given compound is
Explanation : Given,
Percentage of C = 84.4 %
Percentage of H = 15.6 %
Let the mass of compound be 100 g. So, percentages given are taken as mass.
Mass of C = 84.4 g
Mass of H = 15.6 g
To formulate the empirical formula, we need to follow some steps:
Step 1: Converting the given masses into moles.
Moles of Carbon =
Moles of Hydrogen =
Step 2: Calculating the mole ratio of the given elements.
For the mole ratio, we divide each value of the moles by the smallest number of moles calculated which is 7.03 moles.
For Carbon =
For Hydrogen =
Step 3: Taking the mole ratio as their subscripts.
The ratio of C : H = 1 : 2
Hence, the empirical formula for the given compound is