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lorasvet [3.4K]
2 years ago
9

URGENT, TEST DUE AT MIDNIGHT

Chemistry
2 answers:
sweet-ann [11.9K]2 years ago
5 0

Answer:

B is most volatile, A is least volatile

Explanation:

Varvara68 [4.7K]2 years ago
5 0

Answer:

<h3>B is most volatile, <em>a</em><em> </em><em>is</em><em> </em><em>least</em><em> </em><em>volatile</em><em> </em></h3>

Explanation:

<h3><em><u>I</u></em><em><u> </u></em><em><u>hope</u></em><em><u> </u></em><em><u>this</u></em><em><u> </u></em><em><u>helps</u></em><em><u> </u></em><em><u>u</u></em><em><u> </u></em></h3><h3><em><u>have</u></em><em><u> </u></em><em><u>a</u></em><em><u> </u></em><em><u>nice</u></em><em><u> </u></em><em><u>day</u></em><em><u> </u></em><em><u>✌</u></em><em><u>❤</u></em><em><u>☘</u></em></h3>
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allene?

Explanation:

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Where is the picture
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Which of the following electron configurations gives the correct arrangement of the four valence electrons of the carbon atom in
Juliette [100K]

Answer:

D) 2s^12p^3

Explanation:

Carbon.

The electronic configuration is -  

1s^22s^22p^2

Thus, 2s orbital is fully filled and p orbital can singly filled 3 electrons. Thus, Carbon has 2 singly occupied orbitals.

But in methane, CH_4 it forms 4 bonds. So, 1 electron each from 2s orbital jumps to the next orbital in the p subshell.

Thus, the configuration is:-

1s^22s^22p^2

Thus, the valence electron configuration is:-

2s^12p^3

7 0
2 years ago
Sodium hydroxide reacts with aluminum and water to produce hydrogen gas: 2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 NaAl(OH)4(aq) + 3 H
lianna [129]

Answer:

The mass of hydrogen gas formed is 0.205 grams

Explanation:

<u>Step 1:</u> Data given

Mass of 1.83 grams of Al

Mass of NaOH = 4.30 grams

Molar mass of Al = 26.98 g/mol

Molar mass of NaOH = 40 g/mol

<u>Step 2:</u> The balanced equation:

2 Al(s) + 2 NaOH(aq) + 6 H2O(l) → 2 NaAl(OH)4(aq) + 3 H2(g)

<u>Step 3:</u> Calculate moles of Al

Moles Al = mass Al / Molar mass Al

Moles Al = 1.83 grams / 26.98 g/mol

Moles Al = 0.0678 moles

<u>Step 4:</u> Calculate moles of NaOH

Moles NaOH = 4.30 grams / 40 g/mol

Moles NaOH = 0.1075 moles

<u>Step 5</u>: Calculate limiting reactant

For 2 moles of Al, we need 2 moles of NaOH

Aluminium is the limiting reactant. It will completely be consumed ( 0.0678 moles)

NaOH is in excess. There will react 0.0678 moles

There will remain 0.1075 - 0.0678 = 0.0397 moles

<u>Step 6</u>: Calculate moles of hydrogen

For 2 moles of Al, we need 2 moles of NaOH, to produce 3 moles of hydrogen

For 0.0678 moles of Al, there is produced 0.0678 *3/2 = 0.1017 moles of H2

<u>Step 7</u>: Calculate mass of H2

Mass of H2 = Moles H2 * Molar mass of H2

Mass of H2 = 0.1017 moles * 2.02 g/mol

Mass of H2 = 0.205 grams

The mass of hydrogen gas formed is 0.205 grams

6 0
2 years ago
Aluminum reacts with sulfur gas to produce aluminum sulfide
weqwewe [10]

Answer:

What is the question? It looks like a fact.

Explanation:

4 0
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