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charle [14.2K]
2 years ago
15

The admission fee at the Smithsonian Air & Space

Mathematics
1 answer:
mel-nik [20]2 years ago
6 0
A. 1.50c+ 4.00a = 5050 (Money earned)
     c + a =2200 (Guests in the museum) 

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Markus was given dollar bills from his grandfather each day for one week. On the first day he received $1, on the second day he
snow_tiger [21]

Answer:  $127.00

Step-by-step explanation:

you just multiply all the numbers by two then you add everything up. make sure to have a great day, and I really hope that this help! :)

4 0
3 years ago
A surveyor wants to know how many shoppers at a mall like to read books. He surveys 100 people coming out of a bookstore at the
denpristay [2]
Its B. <span>People who shop in bookstores are likely to read more books than those who do not.</span>
4 0
3 years ago
Is there a way to understand inequalities better? I don't get them at all!
AlekseyPX
Ok for inequalities it's this < and > that so here's a example prob 3>2 so as my teacher used it put it "it's like the little number eats the bigger number." For negatives the one that's being eaten would be the one that's the closest to 0 so -3>-5 also alone way of doing this is to make a number line that's another way I was taught how to do these. I hope this helps you!
7 0
3 years ago
At what point on the curve y = 19 2x is the tangent line perpendicular to the line 20x 4y = 1?
Gennadij [26K]

The points are; (7/2, -1/2).

<h3>What is the given point?</h3>

Now the tangent line is given as;20x 4y = 1. When we rewrite it in the slope intercept form, we have the equation as; y = 1 - 20x/4 or y = 1/4 - 5x.

Then to obtain the slope of the curve we have; y = 19 - 2x

dy/dx = 2

Using the relation;

m1m2 = -1

m2 = -1/2

Hence;

y = 1/4 - 5(-1/2)

y = 1/4 + 5/2

y = 7/2

Thus the points are; (7/2, -1/2)

Learn more about normal curve:brainly.com/question/10664419

#SPJ4

7 0
1 year ago
What are the coordinates of the inflection point on the graph of y=(x+1)arctanx
Dennis_Churaev [7]

Inflection point is the point where the second derivative of a graph is zero.

y = (x+1)arctan xy' = (x+1)(arctan x)' + (1)arctan xy' = (x+1)/(x^2+1) + arctan xy'' = (x+1)(1/(1+x^2))' + 1/(1+x^2) + 1/(1+x^2)y'' = (x+1)(-1/(1+x^2)^2)(2x)+2/(1+x^2)y'' = ((x+1)(-2x)+1+x^2)/(1+x^2)^2y'' = (-2x^2-2x+2+2x^2)/(1+x^2)^2y'' = (-2x+2)/(1+x^2)^2

Solving for point of inflection: y'' = 00 = (-2x+2)/(1+x^2)^20 = -2x+2x = 1y(1) = (1+1)arctan(1) = 2 * pi/4 = pi/2

Therefore, E(1, pi/2).


I hope my answer has come to your help. Thank you for posting your question here in Brainly. We hope to answer more of your questions and inquiries soon. Have a nice day ahead!

5 0
3 years ago
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