Answer:
Karen had 45 m and m's candy.
Step-by-step explanation:
Let the number of m and m's candy be 'x'.
Now given:
Karen gave an equal amount of m and m's to herself and four friends.
So we can say that;
Number of people m and m's candy distributed equally = 5
Also Given:
Each person receives m and m's equivalent to the largest one digit number.
Now we know that;
Largest one digit number is 9.
So we can say that;
Each person receives m and m's = 9
We need to find number of m and m's Karen have.
Solution:
So we can say that;
Total number of m and m's Karen have is equal to Number of people m and m's candy distributed equally multiplied by number of m and m's can each person receives.
framing in equation form we get;
Total number of m and m's Karen had = 
Hence Karen had 45 m and m's candy.
Answer:
34
Step-by-step explanation:
cause you had to doit the simple math problem
are you trying to prank on this problem
Answer:
x=12 y=3
Step-by-step explanation:
Since the scale factor is 1:3, that means that the length and width of Q multiplied by 3 gives the corresponding length and width of P.
Similarly, the length and width of P divided by 3 gives the corresponding length and width of Q.
With this, 9/3=3, which is the value of y.
4*3=12, which is the value of x.
Answer:
y = 5cos(πx/4) +11
Step-by-step explanation:
The radius is 5 ft, so that will be the multiplier of the trig function.
The car starts at the top of the wheel, so the appropriate trig function is cosine, which is 1 (its maximum value) when its argument is zero.
The period is 8 seconds, so the argument of the cosine function will be 2π(x/8) = πx/4. This changes by 2π when x changes by 8.
The centerline of the wheel is the sum of the minimum and the radius, so is 6+5 = 11 ft. This is the offset of the scaled cosine function.
Putting that all together, you get
... y = 5cos(π/4x) + 11
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The answer selections don't seem to consistently identify the argument of the trig function properly. We assume that π/4(x) means (πx/4), where this product is the argument of the trig function.