Answer: $127.00
Step-by-step explanation:
you just multiply all the numbers by two then you add everything up. make sure to have a great day, and I really hope that this help! :)
Its B. <span>People who shop in bookstores are likely to read more books than those who do not.</span>
Ok for inequalities it's this < and > that so here's a example prob 3>2 so as my teacher used it put it "it's like the little number eats the bigger number." For negatives the one that's being eaten would be the one that's the closest to 0 so -3>-5 also alone way of doing this is to make a number line that's another way I was taught how to do these. I hope this helps you!
The points are; (7/2, -1/2).
<h3>What is the given point?</h3>
Now the tangent line is given as;20x 4y = 1. When we rewrite it in the slope intercept form, we have the equation as; y = 1 - 20x/4 or y = 1/4 - 5x.
Then to obtain the slope of the curve we have; y = 19 - 2x
dy/dx = 2
Using the relation;
m1m2 = -1
m2 = -1/2
Hence;
y = 1/4 - 5(-1/2)
y = 1/4 + 5/2
y = 7/2
Thus the points are; (7/2, -1/2)
Learn more about normal curve:brainly.com/question/10664419
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Inflection point is the point where the second derivative of a graph is zero.
y = (x+1)arctan xy' = (x+1)(arctan x)' + (1)arctan xy' = (x+1)/(x^2+1) + arctan xy'' = (x+1)(1/(1+x^2))' + 1/(1+x^2) + 1/(1+x^2)y'' = (x+1)(-1/(1+x^2)^2)(2x)+2/(1+x^2)y'' = ((x+1)(-2x)+1+x^2)/(1+x^2)^2y'' = (-2x^2-2x+2+2x^2)/(1+x^2)^2y'' = (-2x+2)/(1+x^2)^2
Solving for point of inflection: y'' = 00 = (-2x+2)/(1+x^2)^20 = -2x+2x = 1y(1) = (1+1)arctan(1) = 2 * pi/4 = pi/2
Therefore, E(1, pi/2).
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