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BartSMP [9]
3 years ago
14

What is the gcf of of -9y^2 + 6y

Mathematics
1 answer:
Valentin [98]3 years ago
5 0

Answer:

3y

Step-by-step explanation:

First find the factors of the terms.  You need to then figure out how many factors match.

-9y² = -1 · 3 · 3 · y · y

6y = 2 · 3 · y

3y is the greatest common factor.

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Find the value of ( 1+cosA) (1-cosA)
Mandarinka [93]

Answer:

sin^2 A

Step-by-step explanation:

first expand the trigonometry

1(1-cosA)+cosA(1-cosA)

=1-cosA+cosA-cos^2 A

= 1-cos^2 A

from trigonometric identity sin^2 A + cos^2 A= 1

sin^2 A= 1- cos^2 A

=sin^2 A

3 0
2 years ago
How would you find if these two triangles are congruent?
nexus9112 [7]
Compare the small marks on the lines of the triangles, if you draw them both out next to each other, are they exactly the same? If so, they’re congruent
7 0
3 years ago
Given the point (4,5) & slope = -4, what is the equation of the line? *
raketka [301]

Answer:

Y= -4x+ 21

Step-by-step explanation:

7 0
3 years ago
Show that 1n^ 3 + 2n + 3n ^2 is divisible by 2 and 3 for all positive integers n.
Dmitry_Shevchenko [17]

Prove:

Using mathemetical induction:

P(n) = n^{3}+2n+3n^{2}

for n=1

P(n)  = 1^{3}+2(1)+3(1)^{2} = 6

It is divisible by 2 and 3

Now, for n=k, n > 0

P(k) = k^{3}+2k+3k^{2}

Assuming P(k) is divisible by 2 and 3:

Now, for n=k+1:

P(k+1) = (k+1)^{3}+2(k+1)+3(k+1)^{2}

P(k+1) = k^{3}+3k^{2}+3k+1+2k+2+3k^{2}+6k+3

P(k+1) = P(k)+3(k^{2}+3k+2)

Since, we assumed that P(k) is divisible by 2 and 3, therefore, P(k+1) is also

divisible by 2 and 3.

Hence, by mathematical induction, P(n) = n^{3}+2n+3n^{2} is divisible by 2 and 3 for all positive integer n.

3 0
3 years ago
Pls help<br><br> Given: △ABC, CM⊥ AB, BC = 5, AB = 7<br> CA = 4 sqrt(2)<br> Find: CM
babymother [125]

Answer:

The general plan is to find BM and from that CM. You need 2 equations to do that.

Step One

Set up the two equations.

(7 - BM)^2 + CM^2 = (4*sqrt(2) ) ^ 2 = 32

BM^2 + CM^2 = 5^2 = 25

Step Two

Subtract the two equations.

(7 - BM)^2 + CM^2  = 32

BM^2 + CM^2         = 25

(7 - BM)^2 - BM^2 = 7               (3)

Step three

Expand the left side of the new equation labeled (3)

49 - 14BM + BM^2 - BM^2 = 7    

Step 4

Simplify And Solve

49 - 14BM = 7              Subtract 49 from both sides.

-49 - 14BM = 7 - 49

- 14BM = - 42              Divide by - 14

BM = -42 / - 14

BM = 3

Step  Five

Find CM

CM^2 + BM^2 = 5^2

CM^2 + 3^2 = 5^2        Subtract 3^2 from both sides.

CM^2 = 25 - 9            

CM^2 = 16                     Take the square root of both sides.        

sqrt(CM^2) = sqrt(16)

CM = 4    < Answer

Step-by-step explanation:

6 0
3 years ago
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