Suppose we add up alternate Fibonacci numbers, Fn-1 + Fn+1; that is, what do ... L(1)=1 and L(3)= 4 so their sum is 5 whereas F(2)=1; L(2)=3 and L(4)= 7 so their ... What is the relationship between F(n-2), and F(n+2)? You should be able to find a ... Fib(N); K (an EVEN number!), Lucas(K) and Fib(K) in each expression like ...

Explanation:

3 0

2 years ago

scientists have a great deal of responsibility why is it important for scientists to communicate their results accurately to peo

Art [367]

So other scientists can try the exact same experiment and see if they both got the same results.

5 0

3 years ago

Mexican hairless dogs are hairless because of a dominant allele of a particular gene. Homozygous dominant dogs die in utero (bef

crimeas [40]

Answer:

50%

Explanation:

Both parent's genotype is Bb because they are hairless and alive.

If it has a homozygous dominant genotype (BB), the dog will die in utero.

If it has a heterozygous genotype (Bb), the dog will be hairless but won't die.

If it has a homozygous dominant genotype (bb), the dog will have hair.

The ratio of BB:Bb:bb is 1:2:1 meaning that there is a 50% probability of having a live hairless puppy.

Hope this helps! <3

8 0

2 years ago

6. The LEAVES contain tiny pigments<br>called

larisa86 [58]

Answer:

chlorophyll

why do i know this lol

7 0

2 years ago