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soldier1979 [14.2K]
3 years ago
13

A fruit bowl contains apples and bananas in the ratio 4 : 5. Two apples are removed changing the ratio to 2 : 3. Work out the to

tal number of fruit that remain in the bowl.​
Mathematics
2 answers:
Akimi4 [234]3 years ago
6 0

Answer:

25

Step-by-step explanation:

Given that the ratio is 4 : 5 = 4x : 5x ( x is a multiplier ), then

4x - 2 : 5x = 2 : 3

Expressing the ratio in fractional form

\frac{4x-2}{5x} = \frac{2}{3} ( cross- multiply )

3(4x - 2) = 10x , distribute left side

12x - 6 = 10x ( subtract 10x from both sides )

2x - 6 = 0 ( add 6 to both sides )

2x = 6 ( divide both sides by 2 )

x = 3

Thus initially there were

4x + 5x = 9x = 9(3) = 27 pieces of fruit

2 apples were removed, leaving 25

tresset_1 [31]3 years ago
3 0

Answer:

25

Step-by-step explanation:

4 : 5. is ratio before two apples were removed.

2 : 3. is ratio after two apples were removed.

combing the two statements will give you the following mathematical statement:

4x-2:5x=2:3 solve for x

3(4x-2)=5x*2

12x - 6=

2x=6

x=3

then 4x + 5x = total ñô fruit

4(3) + 5(3) = total ñô fruit

27= total ñô fruit

remaining fruit=total ñô fruit - 2

remaining fruit=27-2

remaining fruit=25

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Explain the level of uncertainties involve in concept of probability. The next generation of miniaturized wireless capsules with
RUDIKE [14]

Answer:

a) the probability that Both motors will operate satisfactorily in the capsule 0.6222

b) the probability that One motor will operate satisfactorily and the other will not is 0.3556

Step-by-step explanation:

Given that;

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number of motors randomly selected n = 2

let X be number of motors will that will not operate successfully

here, X≅Hyper geometric (x; N,n,m)

The probability mass function of x is;

P (X = x)=  { m }   {N - m }

                  {x }    {n - x}

        ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

                     { N }

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the probability that both motors will operate satisfactorily in the capsule i.e no motor will not operate satisfactory

so

P(X= 0)  = { 2 }    { 10 - 2 }

                 {0 }    { 2 - 0}

        ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

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                     { 2  }

so

P (X = 0)  = { 2 }   { 8}

              {  0 }   { 2  }

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                     { 10 }

                     { 2  }

p(P= 0)=1×28 / 45 = 28/45 = 0.6222

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b)

the probability that one motor will operate satisfactorily and the other will not.

P(X=1)  = { 2 }   { 10 - 2 }

              {  1 }    { 2 - 1  }

        ⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻⁻

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                     { 10 }

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P(X=1)  = 2×8 / 45 = 16/45 = 0.3556

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