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kipiarov [429]
4 years ago
8

Two and seven sixths minus seven sixths

Mathematics
1 answer:
Alecsey [184]4 years ago
6 0

Answer:

2

Step-by-step explanation:

(2 7/6) - 7/6= 2

2 7/6 is just 2+7/6 then subtract 7/6 and get 2.

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Graph the equation to solve the system. y=2x+7 1/2y=x+7/2
vlabodo [156]

Given equation is y=2x+7 and \frac{1}{2}y=x+\frac{7}{2}

Let's simplify the 2nd equation \frac{1}{2}y=x+\frac{7}{2} before we can start graph so that calculation will be easy

\frac{1}{2}y=x+\frac{7}{2}

multiply both sides by 2 to cancel out fractions

2*\frac{1}{2}y=2*x+2*\frac{7}{2}

y=2x+7

which is exactly same as the first equatoin so graph of both will be exactly same and solution will be infinitely many solutions.

y=2x+7 has y-intercept 7 so first point will be (0,7). Slope is 2 so rise 2 unit up then 1 right and graph the new point.


3 0
3 years ago
According to a survey, the average American person watches TV for 3 hours per week. To test if the amount of TV in New York City
Neporo4naja [7]

Answer:

Test statistic (t-value) of this one-mean hypothesis test is -2.422.

Step-by-step explanation:

We are given that according to a survey, the average American person watches TV for 3 hours per week. She surveys 19 New Yorkers randomly and asks them about their amount of TV each week, on average. From the data, the sample mean time is 2.5 hours per week, and the sample standard deviation (s) is 0.9 hours.

We have to test if the amount of TV in New York City is less than the national average.

Let Null Hypothesis, H_0 : \mu \leq 3  {means that the amount of TV in New York City is less than the national average}

Alternate Hypothesis, H_1 : \mu > 3   {means that the amount of TV in New York City is more than the national average}

The test statistics that will be used here is One-sample t-test statistics;

        T.S. = \frac{\bar X - \mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

where, \bar X = sample mean time = 2.5 hours per week

             s = sample standard deviation = 0.09 hours

             n = sample size = 19

So, <u>test statistics</u> = \frac{2.5 - 3}{\frac{0.9}{\sqrt{19} } } ~ t_1_8

                              = -2.422

Therefore, the test statistic (t-value) of this one-mean hypothesis test (with σ unknown) is -2.422.

8 0
3 years ago
Please simplify 10{N + 3).
lana [24]

Answer:

Step-by-step explanation:

I must assume that you meant 10(N + 3).  Let's not mix { with ).

10(N + 3) is as simple as this expression gets.  You could, however, re-write it as 10N + 30.

6 0
3 years ago
Can u help me. i dont know the 2 answers
olchik [2.2K]

Answer:

You have its E because if it's a A percentage you have to turn the inter despara point

3 0
3 years ago
I can help with financial algebra if not just a freebie
yKpoI14uk [10]

Answer:

Well, okay then. I'll consult you if I ever need help. Thanks friend. xx

3 0
3 years ago
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