False. At equilibrium, the rate of forward reaction is equal to the rate of backward reaction. The net concentration of both products and reactants won't change, but the reactions still take place.
Answer:
hello your question is incomplete attached below is the complete question
a) 0.12 M
b) Ka = 3.0 * 10^-7
c) Alizarin Yellow R
Explanation:
<u>A) Determine the concentration of the unknown acid</u>
The PH of the unknown acid before addition of NaOH is ; 3.72 ( weak acid )
First determine the moles of of NaOH
= molarity * volume
= 0.10 M * 30.0 ML = 0.0030 mol
at equivalence point
moles of NaOH = moles of unknown acid = 0.0030 mol
volume of unknown acid = 25.0 mL
Next calculate the concentration of the Acid ( HA )
= moles / volume
= 0.0030 mol / 25.0 mL
= 0.12 M
<u>b) Determine the Ka of the unknown acid </u>
attached below is the detailed solution
Ka = 3.0 * 10^-7
c) The indicator that would be a good choice to use in the titration of this acid with NaOH is ; Alizarin Yellow R . this is because the titration is between a strong base and a weak acid.
Answer:
atoms of C? 2.25 x 1022 atoms C x 1 mole C = 0.037 mol C
Explanation:
How many moles of C are in 2.25 x 1022 atoms of C?
Answer : The atomic mass of chlorine is, 36.723 amu
Explanation :
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:

As we are given that,
Mass of 35-Cl isotope = 35 amu
Percentage abundance of 35-Cl isotope = 13.85 %
Fractional abundance of 35-Cl isotope = 0.1385
Mass of 37-Cl isotope = 37 amu
Percentage abundance of 37-Cl isotope = 86.15 %
Fractional abundance of 37-Cl isotope = 0.8615
Now put all the given values in above formula, we get:
![\text{Average atomic mass }=[(35\times 0.1385)+(37\times 0.8615)]](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20%7D%3D%5B%2835%5Ctimes%200.1385%29%2B%2837%5Ctimes%200.8615%29%5D)

Therefore, the atomic mass of chlorine is, 36.723 amu
Answer:
Single displacement and reduction
Explanation:
In a single-displacement reaction, one element exchanges partners with another.

This is a single-displacement reaction, because the element Ca exchanges partners with H.
This is also a reduction/oxidation (redox) reaction, because the optically active of Ca increases from 0 to +2 (oxidation), while the oxidation number of H decreases from +1 to 0 (reduction),
The most common types of reactions are:
- Combination
- Decomposition
- Single displacement
- Double displacement
- Reduction/oxidation