Answer:
C₁₂H₂₂O₁₁ (C₁₂H₂₂O₁₁ ).
Explanation:
The empirical formula is obtained when we divide the molecular formula with a whole number giving the simplest ratio of all the elements (in whole number).
a) C₁₂H₂₂O₁₁ :
There is no number with which we can divide the ratio further to get a simpler formula hence the molecular formula of the given compound is the empirical formula of the compound. Hence it is correct.
(C₁₂H₂₂O₁₁),
(b) C₈H₁₂O₄
The empirical formula can be obtained by dividing the formula with "4"
The empirical formula would be
(C₂H₃O)
(c) H₂O₂
The empirical formula would be (H₁O₁)
Answer:
"ite"
Explanation:
Se sabe que los elementos del grupo 16 de la tabla prioritaria muestran estados de oxidación o valencias de 2,4 y 6 respectivamente, dependiendo del compuesto formado.
Por ejemplo, el azufre forma los siguientes compuestos;
sulfato de sodio (el azufre tiene una valencia de 6)
Sulfito de sodio (el azufre tiene una valencia de 4)
Sulfuro de sodio (el azufre tiene una valencia de 2)
Por lo tanto, en compuestos en los que exhiben una valencia de 4, la terminación común es "ite"
Answer:
a. The number of neutrons in the nucleus
Explanation:
Having more protons or electrons would change the charge of the atom making it an ion. Neutrons have no charge so the overall charge of the atom is not affected; neutrons also have a relative mass of 1 which is why there are different isotopes.
Hope this helps!
The products : Zn₃(PO₄)₂ (s) + KClO₃ (aq)
<h3>Further explanation</h3>
Given
reaction: Zn(ClO₃)₂ (aq) + K₃PO₄ (aq)
Required
The products
Solution
Double-Replacement reactions : an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product
General formula :
AB + CD ⇒ AD + CB
One of the characteristics of the double replacement reaction is the presence of precipitated compounds
Zn(ClO₃)₂ (aq) + K₃PO₄ (aq) ⇒ Zn₃(PO₄)₂ (s) + KClO₃ (aq)
Zn₃(PO₄)₂ (s)⇒ precipitated compounds, so that this reaction can occur
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