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Anettt [7]
3 years ago
6

Explain how a redox reacation involves electrons in the same way that a neutralization reaction involves protons

Chemistry
1 answer:
lidiya [134]3 years ago
8 0
For the neutralization process: an acid acts as a donor and donates protons to the base. On the other hand, the base acts as an acceptor and accepts the transferred protons. In a nutshell, neutralization is mainly proton transfer process.

As for the redox process: the oxidized material usually transfers electrons to the reduced material. In a nutshell, redox is mainly electron transfer process.
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What volume (in liters) does 3.91 moles of nitrogen gas at 5.35 atm and 323 K occupy
daser333 [38]
Moles   =  n  = 3.91 mol

                  Pressure  =  P  =  5.35 atm

                  Temperature  =  T  =  323 K

                  Volume  =  V  =  ?

Formula used: Ideal Gas Equation is used,

                                        P V  = n R  T
Solving for V,
                                           V  =  n R T / P
Putting Values,
                           V  =  (3.91 mol × 0.0825 atm.L.mol⁻¹.K⁻¹ × 323 K) ÷ 5.35 atm

                         V  =  19.36 L

5 0
3 years ago
how many grams of oxygen gas are needed to produce 10.0 grams of carbon dioxide according to the balanced equation of CH4
Alinara [238K]
Molar mass of :

O2 = 16 * 2 = 32 g/mol

CO2 = 12 + 16 * 2 = 44 g/mol

<span>Balanced chemical equation :
</span>
1 CH4 + 2 O2 = 1 CO2 + 2 H2O
               ↓              ↓
             2 moles     1 mole

2* 32 g O2 ----------> 1* 44 g CO2
     x g O2 ------------> 10.0 g CO2

44 x = 2 * 32*10.0

44 x = 640

x =  \frac{640}{44}

x = 14.54 g of O2





7 0
3 years ago
CAN SOMEONE PLEASE HELP ME I DON’T UNDERSTAND :(
masya89 [10]

Answer:

A supersaturated solution

6 0
3 years ago
Match each statements with the state of matter it describes?
Len [333]

Answer:

Solid  liquids , plasma gas

Explanation:

It retains its shape regardless of the shape of the container

5 0
3 years ago
Identify the limiting reactant in the reaction of iron and chlorine to form FeCl3, of 22.7 g of Fe and 37.2 g of Cl2 are combine
Mice21 [21]

Answer:

3.13 g of Fe remains after the reaction is complete

Explanation:

The first step to begin is determine the reaction:

2Fe + 3Cl₂ → 2FeCl₃

Let's find out the moles of each reactant:

22.7 g / 55.85 g/mol = 0.406 moles of Fe

37.2 g / 70.9 g/mol = 0.525 moles of Cl₂

Ratio is 2:3. 2 moles of iron react with 3 moles of chlorine

Then, 0.406 moles of iron will react with (0.406 . 3)/ 2 = 0.609 moles

We need 0.609 moles of chlorine when we have 0.525 moles, so as we do not have enough Cl₂, this is the limiting reactant.

The excess is the Fe. Let's see:

3 moles of chlorine react with 2 moles of Fe

Then, 0.525 moles of Cl₂ will react with (0.525 . 2) /3 = 0.350 moles

We need 0.350 moles of Fe and we have 0.406; as there are moles of Fe which remains after the reaction is complete, it is ok that Fe is the excess reagent.

0.406 - 0.350 = 0.056 moles of Fe still remains. We convert moles to mass:

0.056 mol . 55.85g / 1 mol = 3.13 g

5 0
3 years ago
Read 2 more answers
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