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Wewaii [24]
3 years ago
5

Use the problem below to answer the question: How many grams of H2 would be formed if 34 grams of carbon reacted with an unlimit

ed amount of H2O? The reaction is: C + H2O → CO + H2 The equation is balanced. The starting substance is carbon, C. The ending substance is hydrogen, H2. Using the periodic table, find the molecular mass of H2. H2 = g/mole
Chemistry
2 answers:
Pavlova-9 [17]3 years ago
6 0
34g C * ( 1 mol / 12.0107 ) * ( 1 mol H2 / 1 mol C ) * ( <span>2.01588 g / 1 mol H2 ) = 5.70657164028741 g H2 = 5.7 g H2

Convert grams of C to moles of C using the given amount of grams and the molar mass ( 12.0107 g/mol ).

Gather the mole ratio from the coefficients in the balanced equation and multiply by the ratio.

Convert moles of H2 to grams of H2 </span> using the given amount of grams and the molar mass ( 2.01588 g/mol )<span>.

Revise your answer to have the correct number of significant figures. </span>
Aleksandr [31]3 years ago
5 0

<u>Answer:</u> The mass of hydrogen gas formed will be 5.66 g

<u>Explanation:</u>

To calculate the number of moles, we use the formula:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}    .....(1)

<u>For Carbon:</u>

Given mass = 34 g

Molar mass = 12 g/mol

Putting values in above equation, we get:

\text{Moles of carbon}=\frac{34g}{12g/mol}=2.83mol

For the given chemical equation:

C+H_2O\rightarrow CO+H_2

By Stoichiometry of the reaction:

1 mole of carbon produces 1 mole of hydrogen gas.

So, 2.83 moles of carbon atom will produce = \frac{1}{1}\times 2.83=2.83mol of hydrogen gas.

Now, to calculate the mass of hydrogen gas, we use equation 1.

Moles of Hydrogen gas = 2.83 mol

Molar mass of hydrogen gas = 2 g/mol

Putting values in equation 1, we get:

2.83mol=\frac{\text{Mass of Hydrogen gas}}{2g/mol}\\\\\text{Mass of Hydrogen gas}=5.66g

Hence, the mass of hydrogen gas formed will be 5.66 g

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kap26 [50]

Answer:

Explanation:

Efficiency of the electric power plant is e=1-\frac{T_{2}}{T_{1}}

Here Temperature of hot source T_{1} = 450^{o}C=450+273=723 K

and Temperature of sink T_{1} = 20^{o}C=20+273=293 K

Hence the efficiency is  e=1-\frac{293}{723}=0.5947=59.47%

Now another formula for thermal efficiency Is

e_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}

Here QI is the of heat taken from source 100 MJ ; Q2 of heat transferred to the sink (river) to be found

W is the of work done and W = QI -Q2

Hence Frome_{therm}=\frac{Q_{1}-Q_{2}}{Q_{1}}=\frac{W}{Q_{1}}

W=e(Q_{1})=(0.5947)(100)=59.47MJ

Hence the of heat transferred to the river Is Q_{2} -W = (100 -59.47=40.53

6 0
3 years ago
Joebert had a rectangular cup and filled it with water. He measured the water's mass and volume. Then he got a density of 1.25g/
ANTONII [103]

Answer:

Percent error = 25%

Explanation:

Given data:

Measured density of water = 1.25 g/mL

Accepted density value of water = 1 g/mL

Percent error = ?

Solution:

Formula:

Percent error = (measured value - accepted value / accepted value) × 100

Now we will put the values in formula:

Percent error = (1.25 g/mL - 1 g/mL /1 g/mL )× 100

Percent error = (0.25 g/mL /1 g/mL )× 100

Percent error = 0.25 × 100

Percent error = 25%

5 0
3 years ago
12.70 L of a gas has a pressure of 0.63 atm. What is the volume of the gas at 105kPa?
Zielflug [23.3K]

Answer: 7.693 L

Explanation:

To calculate the new volume, we use the equation given by Boyle's law. This law states that pressure is directly proportional to the volume of the gas at constant temperature.

The equation given by this law is:

P_1V_1=P_2V_2

where,

P_1\text{ and }V_1 are initial pressure and volume.

P_2\text{ and }V_2 are final pressure and volume.

We are given:

P_1=0.63atm\\V_1=12.70L\\P_2=105kPa=1.04atm(1kPa=0.009atm)\\V_2=?

Putting values in above equation, we get:

0.63\times 12.70mL=1.04\times V_2\\\\V_2=7.693L

Thus new volume of the gas is 7.693 L

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6 0
3 years ago
How many formula units are there in 212 grams of mgCl2
AleksandrR [38]

Formula units are there in 212 grams of MgCl₂ are 830.56

Formula is the empirical of any ionic or covalent network solid compound used as an independent entity for stoichiometric calculations and it is the lowest whole number ratio of ions represented in an ionic compound

Here given data is

MgCl₂ = 212 grams

1 mole of magnesium chloride has mass = 95.211 gram and contains 6.022×10²³formula units of magnesium chloride

Here 212 grams×6.022×10²³form unit of MgCl₂/95.211 gram = 830.56

Know more about magnesium chloride

brainly.com/question/22727305

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