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dimulka [17.4K]
2 years ago
11

Which field of study is shown in the picture? O A. chronology O B. anthropology O C. cartography O D. archaeology​

Chemistry
1 answer:
Svetradugi [14.3K]2 years ago
6 0

The field of study which is shown in the picture is known as archaeology and is denoted as option D.

<h3>What is Archaeology?</h3>

This is defined as the scientific study of the material remains of past human life and activities through gathering of fossils.

This is usually done by a professional referred to as an archaeologist who uses special techniques and methods in the execution of the processes involved.

In the diagram attached in the picture shown below, we can view rocks present which helps to preserve fossils.This is therefore the reason why archaeology was chosen as the most appropriate choice.

Read more about Archaeology here brainly.com/question/928273

#SPJ1

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Complete and balance the following neutralization reaction Ca(OH)2 + H2SO4
Debora [2.8K]

Answer: Ca(OH)2 (aq) + H2SO4 (aq) ---------->  CaSO4(aq) + 2H2O(l)

Explanation:

Since this is a neutralization reaction, the end product would be salt and water. In this equation Calcium will displace hydrogen from the acid because it is more reactive, resulting in the formation of CaSO4 (salt), while the displaced H2 molecule combines with OH molecules to form water.

The equation of the reaction is thus;

Ca(OH)2 (aq) + H2SO4 (aq) ---------->  CaSO4(aq) + H2O(l), in other to balance it, we add ''2'' to the water molecule in the right hand side of the equation.

Balance equation is  

Ca(OH)2 (aq) + H2SO4 (aq) ---------->  CaSO4(aq) + 2H2O(l)

6 0
3 years ago
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Setler79 [48]

Answer:

1 true

Explanation:

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8 0
3 years ago
A solution may contain Ag+, Pb2+, and/or Hg22+. A white precipitate forms when 6 M HCl is added. The precipitate is partially so
omeli [17]

Answer:

All three are present

Explanation:

Addition of 6 M HCl would form precipitates of all the three cations, since the chlorides of these cations are insoluble: AgCl (s), PbCl_2 (s), Hg_2Cl_2 (s).

  • Firstly, the solid produced is partially soluble in hot water. Remember that out of all the three solids, lead(II) choride is the most soluble. It would easily completely dissolve in hot water. This is how we separate it from the remaining precipitate. Therefore, we know that we have lead(II) cations present, as the two remaining chlorides are insoluble even at high temperatures.
  • Secondly, addition of liquid ammonia would form a precipitate with silver: AgCl (s) + 2 NH_3 (aq) + H_2O (l)\rightarrow [Ag(NH_3)_2]OH (s) + HCl (aq); Silver hydroxide at higher temperatures decomposes into black silver oxide: 2 [Ag(NH_3)_2]OH (s)\rightarrow Ag_2O (s) + H_2O (l) + 4 NH_3 (g).
  • Thirdly, we also know we have Hg_2^{2+} in the mixture, since addition of potassium chromate produces a yellow precipitate: Hg_2^{2+} (aq) + CrO_4^{2-} (aq)\rightarrow Hg_2CrO_4 (s). The latter precipitate is yellow.
3 0
4 years ago
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atroni [7]
True, a lunar eclipse occurs when the Moon is between the Sun and Earth
7 0
3 years ago
Ionic or covalent C2H5OH
Afina-wow [57]

Answer:

Covalent  

Explanation:

A molecule of C₂H₅OH has C-C, C-H, C-O, and O-H bonds.

A bond between A and B will be ionic if the difference between their electronegativities (ΔEN) is greater than 1.6.

\begin{array}{ccc}\textbf{Bond} & \textbf{$\Delta$EN} & \textbf{Polarity}\\\text{C-C} & 2.55 - 2.55 = 0.00 & \text{Nonpolar covalent}\\\text{C-H} & 2.55 - 2.20 = 0.35 & \text{Nonpolar covalent}\\\text{C-O} & 3.44 - 2.55 = 0.89 & \text{Polar covalent}\\\text{O-H} & 3.44 - 2.20 = 1.24 & \text{Polar covalent}\\\end{array}

No bond has a large enough ΔEN to be ionic.

C₂H₅OH is a covalent molecule.

6 0
3 years ago
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