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3 years ago

Predict the products of the following reaction: Zn(ClO₃)₂ (aq) + K₃PO₄ (aq)

Chemistry

1 answer:

nika2105 [10]3 years ago

3 0

The products : Zn₃(PO₄)₂ (s) + KClO₃ (aq)

<h3>Further explanation</h3>

Given

reaction: Zn(ClO₃)₂ (aq) + K₃PO₄ (aq)

Required

The products

Solution

Double-Replacement reactions : an ion exchange between two ion compounds in the reactant to form two new ion compounds in the product

General formula :

AB + CD ⇒ AD + CB

One of the characteristics of the double replacement reaction is the presence of precipitated compounds

Zn(ClO₃)₂ (aq) + K₃PO₄ (aq) ⇒ Zn₃(PO₄)₂ (s) + KClO₃ (aq)

Zn₃(PO₄)₂ (s)⇒ precipitated compounds, so that this reaction can occur

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A beaker with 1.60×102 mL of an acetic acid buffer with a pH of 5.000 is sitting on a benchtop. The total molarity of acid and c

stich3 [128]

Answer:

The pH will change 0.16 ( from 5.00 to 4.84)

Explanation:

Step 1: Data given

volume of acetic acid buffer = 160 mL

The total molarity of acid and conjugate base in this buffer is 0.100 M

A student adds 7.10 mL of a 0.460 M HCl solution to the beaker.

The pKa of acetic acid is 4.740

pH = 5.00

Step 2: Calculate concentration of acid

Consider x = concentration acid

Consider y = concentration conjugate base

x + y = 0.100

5.00 = 4.740 + log y/x

5.00 - 4.740 = log y/x

0.26 = log y/x

10^0.26 =1.82 = y/x

1.82 x = y

Since x+y = 0.100

x + 1.82 x = 0.100

2.82 x = 0.100

x =0.0355 M = concentration acid

Step 3: Calculate concentration of conjugate base

y = 0.100 - x

0.100 - 0.0355 =0.0645 M= concentration conjugate base

Step 4: Calculate moles of acid

Moles = volume * molarity

moles acid = 0.160 L * 0.0355 M= 0.00568 moles

Step 5: Calculate moles of conjugate base

moles conjugate base = 0.0645 M * 0.160 L=0.01032 moles

Step 6: Calculate moles HCl

moles HCl = 7.10 * 10^-3 L * 0.460 M=0.003266 moles

Step 7: Calculate new moles

A- + H+ = HA

moles conjugate base = 0.01032 - 0.003266 =0.007054 moles

moles acid = 0.00568 + 0.003266=0.008946 moles

Step 8: Calculate the total volume

total volume = 160 + 7.10 = 167.1 mL = 0.1671 L

Step 9: Calculate the concentration of the acid

concentration acid = 0.008946/ 0.1671 =0.0535 M

Step 10: Calculate the concentration of conjugate base

concentration conjugate base = 0.007054/ 0.1671 =0.0422 M

Step 11: Calculate the pH

pH = 4.740 + log 0.0535/ 0.0422=4.84

change pH = 5.00 - 4.84=0.16

The pH will change 0.16

5 0

3 years ago

Calculate the number of moles of an ideal gas if it occupies 1750 dm3 under 125,000 Pa at a temperature of 127 C.

Phoenix [80]

Hey there!

* Converts 1750 dm³ in liters :

1 dm³ = 1 L so 1750 dm³ = 1750 liters

* Convertes 125,000 Pa in atm :

1 Pa = 9.86*10⁻⁶ atm so 9.86*10⁻⁶ / 125,000 => 1.233 atm

* Convertes 127ºC in K :

127 + 273.15 => 400.15 K

R = 0.082 atm.L/mol.K

Finally, it uses an equation of clapeyron :

p * V = n * R * T

1.233 * 1750 = n * 0.082 * 400.15

2157.75 = n * 32.8123

n = 2157.75 / 32.8123

n = 65.76 moles

hope this helps!

5 0

3 years ago

Read 2 more answers

If a solid has a density of 4.0 g/cm^3, what volume of the solid has a mass<br> of 24 g? Show work.

Mrrafil [7]

Answer:

<h2>Volume = 6 cm³</h2>

Explanation:

Density of a substance is given by

$Density = \frac{mass}{volume}$

From the question

Density = 4.0 g/cm³

mass = 24g

Substitute the values into the above formula and solve for the volume

That's

$4 = \frac{24}{v} \\4v = 24$

Divide both sides by 4

v = 6

We have the final answer as

<h3>Volume = 6 cm³</h3>

Hope this helps you

8 0

3 years ago

At 100 degrees Celsius, the ion product for pure water is Kw= 51.3*10^-14. What is the pOH of water at this temperature? A) 7.00

Levart [38]

7.86 is the pOH of water at this temperature of 100 degrees celsius.

Option E is the right answer.

Explanation:

Data given:

Kw = 51.3 x $10^{-14}$

pOH = ?

we know that pure water is neutral and will have pH pf 7.

The equation for relation between Kw and H+ and OH- ion is given by:

Kw = [H+] [OH-}

here the concentration of H+ ion and OH- ion is equal

so, [H+]= [OH-]

Putting the values in the equation of Kw

pKw = -log[Kw]

pKw = -log [51.3 x $10^{-14}$ ]

pKw = 12.28

since H+ ion OH ion concentration is equal the pH of water is half i.e. 6.14

Now, pOH is calculated by using the equation:

14 = pOH + pH

14- 6.14 = pOH

pOH = 7.86

8 0

3 years ago

The product of alpha decay of the Nobelium isotope 259No is

Svet_ta [14]

Answer:

Nobelium is made by the bombardment of curium (Cm) with carbon nuclei. Its most stable isotope, 259No, has a half-life of 58 minutes and decays to Fermium (255Fm) through alpha decay or to Mendelevium (259Md) through electron capture.

Explanation:

7 0

3 years ago