What was the normal perception of a scientist up until the seventeenth century?

Using the equation below, calculate the number of grams of H2O that are formed from the reaction of 34.0 g of NH3.

Mumz [18]

Answer:

54 grams of H₂O

Explanation:

4NH₃ + 3O₂ → 2N₂ + 6H₂O

Ratio is 4:6.

Let's convert the mass of ammonia in moles

Mass / Molar mass = Mol

34 g / 17 g/m = 2 moles

If 4 moles of ammonia are needed to produce 6 mol of water

2 mol of NH₃ will produce ( 2 .6 )/4 = 3 moles

Molar mass water = 18 g/m

Mass = mol . molar mass → 3 m . 18 g/m = 54 grams

8 0

3 years ago

When balancing a chemical equation, what are the large numbers that we adjust?

Nata [24]

Answer:

Coefficients

Explanation:

Chemical equations are first written as a skeleton equation, which includes how many atoms each element and compound has. Skeleton equations are not 'balanced' because the number of atoms of each element on the left side (reactants) is not equal to the right side (products).

To balance a chemical equation, you can write coefficients in front of single elements and compounds. The coefficient multiplies with each single element and with each element in the compound.

For example, in this skeleton equation:

H₂ + Cl₂ => HCl

Reactants: Products:

2 hydrogen 1 hydrogen

2 chlorine 1 chlorine

Write the coefficient 2 in the products.

H₂ + Cl₂ => 2HCl

Now both reactant and product sides have 2 chlorine and 2 hydrogen, so the equation is balanced.

6 0

4 years ago

(b) Do compounds of hydrogen exhibit a relatively large or small kinetic isotope effect? Explain.

joja [24]

Compounds of hydrogen exhibit a relatively large kinetic isotope effect.

The phenomenon known as the kinetic isotope effect (KIE) is brought on by the variable reaction speeds that are displayed by isotopically substituted compounds. When it comes to studying reaction kinetics, mechanisms, and solvent effects, isotope effects like KIEs are invaluable tools in both physical and biological sciences.

The phenomenon known as the kinetic isotope effect (KIE) is brought on by the variable reaction speeds that are displayed by isotopically substituted compounds. When it comes to studying reaction kinetics, mechanisms, and solvent effects, isotope effects like KIEs are invaluable tools in both physical and biological sciences. The replacement of hydrogen with deuterium is a highly frequent isotope substitution. The ratio kH/kD, which describes this as a "deuterium effect," is used to measure it. Due to the proportion, significant effects are observed.

Learn more about kinetic isotope effect here:

brainly.com/question/20388488

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6 0

2 years ago

A 6.1-kg solid sphere, made of metal whose density is 2600 kg/m3, is suspended by a cord. When the sphere is immersed in a liqui

deff fn [24]

Answer:

Density of the liquid = 1470.43 kg/m³

Explanation:

Given:

Mass of solid sphere(m) = 6.1 kg

Density of the metal = 2600 kg/m³

Thus volume of the liquid :

$Volume(V)=\frac{Mass(m)}{Density (\rho)}$

Volume of the sphere = 6.1 kg/2600 kg/m³ = 0.002346 m³

The volume of water displaced is equal to the volume of sphere (Archimedes' principle)

Volume displaced = 0.002346 m³

Buoyant force = $\rho\times gV$

Where

$\rho$ is the density of the fluid

g is the acceleration due to gravity

V is the volume displaced

The free body diagram of the sphere is shown in image.

According to image:

$mg=\rho\times gV+T$

Acceleration due to gravity = 9.81 ms⁻²

Tension force = 26 N

Applying in the equation to find the density of the liquid as:

$6.1\times 9.81=\rho\times 9.81\times 0.002346+26$

$33.841=\rho\times 9.81\times 0.002346$

$\rho=\frac{33.841}{9.81\times 0.002346}$

$\rho=1470.43 kgm^3$

<u>Thus, the density of the liquid = 1470.43 kg/m³</u>

6 0

4 years ago

If 4.35 grams of zinc metal react with 35.8 grams of silver nitrate, how many grams of silver metal can be formed and how many g

vaieri [72.5K]

The balanced chemical reaction is written as:

<span>Zn + 2AgNO3 = Zn(NO3)2 + 2Ag

To determine the grams of silver metal that is being produced, it is important to first determine which is the limiting reactant and the excess reactant from the given initial amounts. We do as follows:

4.35 g Zn ( 1 mol / 65.38 g ) ( 2 mol AgNO3 / 1 mol Zn ) = 0.1331 mol AgNO3 needed
35.8 g AgNO3 ( 1 mol / 169.87 g ) ( 1 mol Zn / 2 mol AgNO3 ) = 0.1054 mol Zn needed

Therefore, the limiting reactant would be the zinc metal since it would be consumed completely in the reaction. The excess amount of AgNO3 would be:

0.2107 mol AgNO3 - 0.1331 mol AgNO3 = 0.0776 mol AgNO3 left ( 169.87 g / 1 mol ) = 13.19 g AgNO3 left

0.0665 mol Zn ( 2 mol Ag / 1 mol Zn) ( 107.9 g / 1 mol) = 14.3581 g Ag produced</span>

5 0

4 years ago