Please help me this is an easy science question where you put the correct lettered answer in the small chart. Please help you ge
t many points!
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Alkenes on reacting with ozone results in the formation of ozonide which undergo reductive cleavage in presence of dimethyl sulfide to form carbonyl compounds (aldehyde or ketone). Whereas in presence of hydrogen peroxide it undergoes oxidative cleavage to form carboxylic acids or ketones.
Since, A alkene yields 4-heptanone only on treatment with ozone and DMS thus, it implies that both the chains on the side of the double-bond are similar the product is 4-heptanone that means the double bond is present between the chains at the 4th carbon. Therefore the structure of compound A is 4,5-dipropyloct-4-ene.
The reaction is as shown in the image.
The reaction of A with m-CPBA (meta-perchlorobenzoic acid) followed by aqueous acid is shown in the image.
m-CPBA (meta-perchlorobenzoic acid) is a peracid and forms epoxides on reacting with alkenes.
Above question is incomplete. Complete question is attached below
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Correct Answer: Option D i.e. CH3CH2CH2CH2CH3
Reason:
Isomers are the compounds having same molecular formula, but different structural formula.
The molecular formula of the compound is C5H12
The compound present is question (i.e. 2-methyl butane) and option D (n-pentane) has same molecular formula. Hence, they are isomers.
However, compound present in option A, is the same compound provided in question. Hence, it is not an isomer. Compounds reported in option B and C has one carbon atom less and more, respectively as compared to the compound reported in question. Hence, they are also not isomers.
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Correct Answer: Option D i.e. CH3CH2CH2CH2CH3
Reason:
Isomers are the compounds having same molecular formula, but different structural formula.
The molecular formula of the compound is C5H12
The compound present is question (i.e. 2-methyl butane) and option D (n-pentane) has same molecular formula. Hence, they are isomers.
However, compound present in option A, is the same compound provided in question. Hence, it is not an isomer. Compounds reported in option B and C has one carbon atom less and more, respectively as compared to the compound reported in question. Hence, they are also not isomers.