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Ivahew [28]
3 years ago
6

How might a molecule with two strong bond dipoles have no molecular dipole at all?

Chemistry
1 answer:
Reil [10]3 years ago
5 0
 A molecule with two strong bond dipoles can have no molecular dipole if the bond dipoles cancel each other out by pointing in exactly opposite directions. For example, in carbon dioxide (a linear molecule), the carbon-oxygen bonds have a <span>large dipole moment. However, because one dipole points to the left and the other to the right the dipole is cancelled.</span>
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Determine the net number of sigma bonds, the net number of pi bonds, and the overall bond order for N2+. Use 0.5 to indicate a f
trapecia [35]

Answer:

Net number of sigma bonds = 1

Net number of pi bonds = 2

Overall bond order = 3

Explanation:

Electronic configuration of N2 ia  

1s2 2s2 2p3

There is head to head overlap in pz orbital. Thus, there is one sigma bond

Pi bond is formed whenever there is side wise overlapping. Since both px and py undergoes overlapping to form pi bond, there are two pi bonds

Bond order = 0.5 (bonding electron – antibonding electron)

= 0.5 (8-2) = 0.5*6 = 3

5 0
3 years ago
What was the main reason the Federalists wanted
Novay_Z [31]
The national government was too weak to solve the nation's problems. 

The Articles of Confederation were only meant to be temporary, like a stand in, until a better document, eventually known as the constitution, could be created.
5 0
4 years ago
Read 2 more answers
The diagram shows Niels Bohr’s model of an atom.
PtichkaEL [24]

Answer:

Energy is absorbed, and an emission line is produced.

Explanation:

Electrons are present and revolving continuously in the orbits that are present around the nucleus. The energy of electron are fixed and unable to move to other orbits due to the strong attractive force of the proton which is present in the nucleus of the atom. If the electron wants to jump from the first energy level to the second energy level, so the electron has to absorb enough energy which can overcome the attractive force of proton.

4 0
3 years ago
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Determine how many atoms of pure silver will be created when 19.83 x 1023 atoms of copper are used in the following reaction:
Lubov Fominskaja [6]

Answer:

\boxed{3.966 \times 10^{24}\text{ atoms of Ag}}

Explanation:

(a) Balanced equation

Cu + 2AgNO₃ ⟶ Cu(NO₃)₂+ 2Ag

(b) Calculation

You want to convert atoms of Cu to atoms of Ag.

The atomic ratio is ratio is 2 atoms Ag:1 atom Cu

\text{Atoms of Ag} = 19.83 \times 10^{23}\text{atoms Cu} \times \dfrac{\text{2 atoms Ag}}{\text{1 atom Cu}}\\\\= 3.966 \times 10^{24}\text{ atoms of Ag}\\\\\text{The reaction will produce }\boxed{\mathbf{3.966 \times 10^{24}}\textbf{ atoms of Ag}}

4 0
3 years ago
Read 2 more answers
Please help!!! <br><br> Tysm!! Xxxx
KiRa [710]

1) The amount of PbS produced will be 16.27 grams

2: The amount of Fe produced will be 118.72 grams.

<h3>Stoichiometric problems</h3>

1) The equation is balanced. The mole ratio of lead (II) acetate to the PbS is 1:1.

Mole of 22.11 lead acetate = 22.11/ 325.29 = 0.06797 moles

Equivalent mole of PbS = 0.06797 moles

Mass of PbS = 0.06797 x 239.3 = 16.27 grams

2) from the equation, the mole ratio of Al to Fe is 1:1.

Mole of 57.2 g Al = 57.2/26.98 = 2.12 moles

Equivalent mole of Fe = 2.12 moles

Mass of Fe = 2.12 x 56 = 118.72 grams.

More on stoichiometric problems can be found here: brainly.com/question/14465605

#SPJ1

3 0
2 years ago
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