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3 years ago

How might a molecule with two strong bond dipoles have no molecular dipole at all?

1 answer:

5 0

A molecule with two strong bond dipoles can have no molecular dipole if the bond dipoles cancel each other out by pointing in exactly opposite directions. For example, in carbon dioxide (a linear molecule), the carbon-oxygen bonds have a <span>large dipole moment. However, because one dipole points to the left and the other to the right the dipole is cancelled.</span>

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Which of the following will have the slowest rate of diffusion at a given temperature?

marysya [2.9K]

<h3>Answer:</h3>

Chlorine gas (Cl₂)

<h3>Explanation:</h3>

According to the Graham's law of diffusion, the diffusion rate of a gas is inversely proportional to the square root of its density or molar mass.
Therefore, a lighter gas will diffuse faster at a given temperature compared to a heavy gas.
Consequently, the heavier a gas is then the denser it is and the slower it diffuses at a given temperature and vice versa.

In this case we are given gases, CI₂

, H₂,He and Ne.

We are required to identify the gas that will diffuse at the slowest rate.
In other words we are required to determine the heaviest gas.

Looking at the molar mass of the gases given;

Cl₂- 70.91 g/mol

H₂- 2.02 g/mol

He - 4.00 g/mol

Ne- 20.18 g/mol

Therefore, chlorine gas is the heaviest and thus will diffuse at the slowest rate among the choices given.

8 0

3 years ago

A helium-filled balloon has a volume of 2.75 L at 20.°C. The volume of the

omeli [17]

Answer: The outside temperature is 262.1K or -10.9°C

Explanation:

Given that,

Original volume V1 = 2.75 L

Original temperature T1 = 20.0°C

Since unit of temperature is Kelvin, convert 20°C to Kelvin by adding 273 to 20°C

(20.0°C + 273K = 293K)

Outside volume V2 = 2.46 L

Outside temperature T2 = ?

Since volume and temperature are given while pressure is constant, apply the formula for Charle's law

V1/T1 = V2/T2

2.75L/293K = 2.46L/T2

To get the value of T2, cross multiply

2.75L x T2 = 2.46L x 293K

2.75LT2 = 720.78LK

Divide both sides by 2.75L

2.75LT2/ 2.75L = 720.78LK/2.75L

T2 = 262.1K

Hence, the outside temperature in Kelvin is 262.1K. Then, obtain outside temperature in Celsius by subtracting 273 from 262.1K

i.e 262.1K - 273 = -10.9°C

Thus, the outside temperature is 262.1K, or -10.9°C

5 0

3 years ago

Does uranium or barium nucleus have a stronger net force holding its protons

kondaur [170]

Nuclear binding energy is the energy that would be required to disassemble the nucleus of an atom into its component parts. These component parts are netrons and protons, which are collectively called nucleons

8 0

2 years ago

When magma goes down into the lower part of the mantie where it is recycled and may come right back up the ocean ridge is called

maksim [4K]

Subduction zone is the answer

4 0

3 years ago

For the endothermic formation of sulfuric acid H2O(g) + SO3(g) ↔ H2SO4(g) _______ the pressure of the system and ________ the te

coldgirl [10]

Answer: Option (1) is the correct answer.

Explanation:

As per Le Chatelier's principle, any disturbance caused in an equilibrium reaction will tend to shift the equilibrium in a direction away from the disturbance.

For example, $H_{2}O(g) + SO_{3}(g) \rightleftarrow H_{2}SO_{4}(g)$

As this given reaction is endothermic in the forward direction and exothermic in the backward direction. Thus, in order to shift the reaction on left side we need to decrease the temperature.

Also, the number of moles are more on reactant side as compared to product side. So, when we decrease the number of moles on reactant side then the equilibrium will shift on left side.

Therefore, we can conclude that for the given reaction decreasing the pressure of the system and lowering the temperature of the system would shift the reaction to the left.

7 0

3 years ago