The given concentration of boric acid = 0.0500 M
Required volume of the solution = 2 L
Molarity is the moles of solute present per liter solution. So 0.0500 M boric acid has 0.0500 mol boric acid present in 1 L solution.
Calculating the moles of 0.0500 M boric acid present in 2 L solution:

Converting moles of boric acid to mass:

Therefore, 6.183 g boric acid when dissolved and made up to 2 L with distilled water gives 0.0500 M solution.
Answer: Antarctica or anywhere
Explanation:
I hope this helps im not sure if I’m correct but I’m sure u can find them anywhere cold
Answer:
B . Water molecules can collide with other particles more than neon atoms can.
Answer:
2.13g
Explanation:
Atomic mass of CO2 = 12 + 32 = 44g/Mol
Atomic mass of C3H8 = 36 + 8 = 44g/Mol
Reaction
C3H8 + 5O2 --> 3CO2 + 4H2O
3CO2 = 6.39g
Required C3H8 = (6.39/(44 x 3)) x 44 = 2.13g
A
Industry uses only about 18% while the others use around 70-90% of water.