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Nezavi [6.7K]
3 years ago
5

Factorise

y%7D" id="TexFormula1" title=" \sf{ {x}^{2} - {y}^{2} - x + y}" alt=" \sf{ {x}^{2} - {y}^{2} - x + y}" align="absmiddle" class="latex-formula">
Show workings too! ​
Mathematics
2 answers:
dem82 [27]3 years ago
8 0

Answer:

(x-y) (x+y-1)

Step-by-step explanation:

x2-y2-x+y

= (x-y) (x+y) - (x-y)

= (x-y) (x+y-1)

9966 [12]3 years ago
6 0

Answer:

(x-y) (x+y-1)

Step-by-step explanation:

x^2-y^2-x+y

(x-y) (x+y) - (x-y)

(x-y) (x+y-1)

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You earn $102 for doing 12 hours of yard work. Your friend earns $120 working at a store for 15 hours.
krek1111 [17]

Answer:

You earn more per hour and you would get $127.50

Step-by-step explanation:

You can find how much money you get per hour by dividing! 102 divided by 12 is 8.5 and 120 divided by 15 is 8 so you get more!

3 0
3 years ago
Can you solve it, please
weeeeeb [17]

Answer:20

Step-by-step explanation:

3.1 *4.2=13.02 12.4*21=260.4 260.4/13.02=20

8 0
2 years ago
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For homework a student had to complete 15 problems total. If she finished 6 problems in class, what is the ratio of problems she
nexus9112 [7]

Well if the student already finished 6 problems out of 15, there are 15-6 = 9 homework questions she still has to finish.

Still needs to complete: 9.

Already finished: 6

9 : 6.

Simplified: 3 : 2

6 0
3 years ago
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Which graph can be used to find the solution(s) to x2-4x+4=2x+1+x2?
Damm [24]
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4 0
3 years ago
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Using Euclid's division algorithm prove that : 847,2160 are co-primes
AysviL [449]
Definition of eo-primes or relatively primes: Two numbers are said to be co-prime or relatively prime If their HCF IS 1 Hence to prove 847 and 2160 as co-prime numbers we will find their HCF and which should be 1

New steps to find HCF will be as under

2160 = 847 x 2+ 466
847 = 466 ×1 +381
466 = 381 x 1 + 85
381 =85 x 4+ 41
85 =41 x 2+3
41 =3 x 13+ 2
3 =2 x 1+1
2 =1 x 2+0

Therefore, the HCF=1 Hence, the numbers are co-primes (relatively prime).
5 0
3 years ago
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