well, Diego is 4 now, so by his 18th birthday that'll be 14 years later.
![~~~~~~ \textit{Simple Interest Earned Amount} \\\\ A=P(1+rt)\qquad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill & \$1600\\ r=rate\to 8.25\%\to \frac{8.25}{100}\dotfill &0.0825\\ t=years\dotfill &14 \end{cases} \\\\\\ A=1600[1+(0.0825)(14)]\implies A=1600(2.155)\implies A=3448](https://tex.z-dn.net/?f=~~~~~~%20%5Ctextit%7BSimple%20Interest%20Earned%20Amount%7D%20%5C%5C%5C%5C%20A%3DP%281%2Brt%29%5Cqquad%20%5Cbegin%7Bcases%7D%20A%3D%5Ctextit%7Baccumulated%20amount%7D%5C%5C%20P%3D%5Ctextit%7Boriginal%20amount%20deposited%7D%5Cdotfill%20%26%20%5C%241600%5C%5C%20r%3Drate%5Cto%208.25%5C%25%5Cto%20%5Cfrac%7B8.25%7D%7B100%7D%5Cdotfill%20%260.0825%5C%5C%20t%3Dyears%5Cdotfill%20%2614%20%5Cend%7Bcases%7D%20%5C%5C%5C%5C%5C%5C%20A%3D1600%5B1%2B%280.0825%29%2814%29%5D%5Cimplies%20A%3D1600%282.155%29%5Cimplies%20A%3D3448)
<h3>
Answer: x = 7</h3>
Explanation:
Segment addition postulate
CD+DE = CE
this basically is the idea of gluing smaller pieces together to get a larger structure. We can go in reverse to break up a large item into smaller bits. This is assuming there is no leftovers, overlaps, or parts wasted/lost.
CD = 9
DE = 3x+6
CE = 36
----
CD+DE = CE
9+3x+6 = 36
3x+15 = 36
3x = 36-15
3x = 21
x = 21/3
x = 7
-----
If x = 7, then
DE = 3x+6 = 3*7+6 = 21+6 = 27
and
CD+DE = 9+27 = 36 = CE
confirming our answer
Answer:
y = -3/8(x + 2)^2 + 8
Step-by-step explanation:
vertex form is
y = a(x - b)^2 + c where a is a constant and (b,c) is the vertex.
The maximum is at (-2, 8) because x 8 = height and x =-2 is equn. of symmetry
So here we have
y = a(x - (-2))^2 + 8
y = a(x + 2)^2 + 8
Now at the point (-6, 2):
2 = a(-6+2)^2 + 8
2 = 16a + 8
16a = -6
1 = -3/8.
So our equation is y = 3/8(x + 2)^2 + 8
