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4 years ago

Find the value of x, rounded to the nearest tenth.

Mathematics

1 answer:

Mashcka [7]4 years ago

3 0

It’d be 12.458 , rounded to the nearest tenth makes it 12.5. Hopefully, I helped.

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julia-pushkina [17]

Answer:

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Step-by-step explanation:

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3 years ago

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Solve appropriate word problems by modeling them with linear equations in two variables.

Nesterboy [21]

The cost of production equation is:

C = 10n + 20000

Solution:

The equation representing the cost, C, of producing n tires at Royal Tires Co. can be written as:

C = mn + f

Where,

C = cost

n = number of tires

f = company's fixed cost

It costs $30,000 to produce 1,000 tires while it costs $50,000 to produce 3,000 tires

Therefore,

30, 000 = m(1000) + f

50, 000 = m(3000) + f

Which is,

1000m + f = 30000 ------- eqn 1

3000m + f = 50000 ------- eqn 2

Subtract eqn 1 from eqn 2

3000m + f = 50000

1000m + f = 30000

( - ) -------------------

2000m = 20,000

m = 10

Substitute m = 10 in eqn 1

1000(10) + f = 30000

f = 30000 - 10000

f = 20,000

Thus the equation is:

C = 10n + 20000

6 0

4 years ago

Which side lengths form a right triangle?

vampirchik [111]

Answer:

A and C

Step-by-step explanation:

$= \sqrt{ {5}^{2} + ( \sqrt{6})^{2} } \\ = \sqrt{25 + 6} \\ = \sqrt{31}$

$= \sqrt{ {9}^{2} + {12}^{2} } \\ = \sqrt{81 + 144} \\ = \sqrt{225} \\ = 15$

5 0

3 years ago

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Mai wants to make an open top box by cutting out corners of a square piece of cardboard and folding up the sides. The cardboard

Bumek [7]

Answer:

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

The domain for x is all real numbers greater than zero and less than 5 com

Step-by-step explanation:

The question is

What is the volume of the open top box as a function of the side length x in cm of the square cutouts?

see the attached figure to better understand the problem

Let

x -----> the side length in cm of the square cutouts

we know that

The volume of the open top box is

$V=LWH$

we have

$L=(10-2x)\ cm$

$W=(10-2x)\ cm$

$H=x)\ cm$

substitute

$V(x)=(10-2x)(10-2x)x\\\\V(x)=(100-40x+4x^{2})x\\\\V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

Find the domain for x

we know that

$(10-2x) > 0\\10> 2x\\ 5 > x\\x < 5\ cm$

The domain is the interval (0,5)

The domain is all real numbers greater than zero and less than 5 cm

therefore

The volume of the open top box as a function of the side length x in cm of the square cutouts is

$V(x)=(4x^{3}-40x^{2}+100x)\ cm^3$

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3 years ago

8x + 12 = 4r - 16 find r

Ber [7]

After r duhh IM SORRY

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3 years ago

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