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professor190 [17]
3 years ago
11

How many grams are in 88.1 moles of magnesium?

Chemistry
1 answer:
rjkz [21]3 years ago
4 0
For getting the result of this problem, the knowledge of periodic table is very important. From the periodic table we come to know that. The knowledge of atomic mass of magnesium is also required to solve the problem.
1 mole of magnesium = 24.3 gm
88.1 moles of magnesium = (24.3 * 88.1) gms
                                           = 2140.83 gms
So 2140.83 grams are there in 88.1 moles of magnesium.
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Oxygen gas generated in the thermal decomposition of potassium chlorate is collected over water. The volume of gas collected is
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<h3>How to determine the mole of oxygen produced </h3>

We'll begin by obtaining the number of mole of oxygen gas produced from the reaction. This can be obtained by using the ideal gas equation as illustrated below:

  • Volume (V) = 0.128 L
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PV = nRT

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Thus, the number of mole of oxygen gas produced is 0.0051 mole

<h3>How to determine the mass of oxygen collected</h3>

Haven obtain the number of mole of oxygen gas produced, we can determine the mass of the oxygen produced as follow:'

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  • Molar mass of oxygen gas = 32 g/mole
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Mole = mass / molar mass

0.0051 = mass of oxygen / 32

Cross multiply

Mass of oxygen = 0.0051 × 32

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Thus, we can conclude that the mass of oxygen gas collected is 0.16 g

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