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Softa [21]
3 years ago
14

Equations can be balanced by using the half-reaction method. Which step should be completed immediately after finding the oxidat

ion states of atoms
A inserting the coefficients
B balancing the half reactions
C identifying the half reactions
D inspecting the number of atoms
Chemistry
2 answers:
aleksklad [387]3 years ago
8 0

Answer:

C identifying the half reactions

Explanation:

Once we have calculated the oxidation numbers of different elements the next step is to figure out the oxidation and reduction half reaction. If the oxidation number of the element increases it is said t have been oxidized, and when the oxidation number of the element decreases it is said to have been reduced.

love history [14]3 years ago
5 0
Nice question! This is a controversial topic about when or should you at all see the value reaction. I definitely feel the answer would be "C". There are quit numismatic out comes when it comes to this but I'm glad. Cheers
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6. How many moles of water would require 92.048 kJ of heat to raise its temperature from 34.0 °C to 100.0 °C? (3 marks)​
scoray [572]

Taking into account the definition of calorimetry, 0.0185 moles of water are required.

<h3>Calorimetry</h3>

Calorimetry is the measurement and calculation of the amounts of heat exchanged by a body or a system.

Sensible heat is defined as the amount of heat that a body absorbs or releases without any changes in its physical state (phase change).

So, the equation that allows to calculate heat exchanges is:

Q = c× m× ΔT

where Q is the heat exchanged by a body of mass m, made up of a specific heat substance c and where ΔT is the temperature variation.

<h3>Mass of water required</h3>

In this case, you know:

  • Heat= 92.048 kJ
  • Mass of water = ?
  • Initial temperature of water= 34 ºC
  • Final temperature of water= 100 ºC
  • Specific heat of water = 4.186 \frac{J}{gC}

Replacing in the expression to calculate heat exchanges:

92.048 kJ = 4.186 \frac{J}{gC}× m× (100 °C -34 °C)

92.048 kJ = 4.186 \frac{J}{gC}× m× 66 °C

m= 92.048 kJ ÷ (4.186 \frac{J}{gC}× 66 °C)

<u><em>m= 0.333 grams</em></u>

<h3>Moles of water required</h3>

Being the molar mass of water 18 \frac{g}{mole}, that is, the amount of mass that a substance contains in one mole, the moles of water required can be calculated as:

amount of moles=0.333 gramsx\frac{1 mole}{18 grams}

<u><em>amount of moles= 0.0185 moles</em></u>

Finally, 0.0185 moles of water are required.

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