All categories

4 years ago

WILL GIVE BRAINLY

1 answer:

8 0

KCIO3 → KCI + O2

First you have to count all the atoms of each element in both sides of the reaction, in this case:
Left side: there is one K atom, one Cl atom and 3 O atoms
Right side: there is one K atom, one Cl atom and 2 O atoms

K and Cl are balanced but O isn't
To balance O you can add a coefficient to O2 in the right side of the equation like this:

KCIO3 → KCI +3 O2

Now you have 6 oxygen atoms in the right side but only 3 in the left side, so you can add a coefficient to KClO3:

2KCIO3 → KCI +3 O2

And finally, Balance K and Cl again by adding a 2 as a coefficient for KCl

2KCIO3 → 2KCI +3 O2

Now both sides have the same amount of atoms of each element (2 K atoms, 2 Cl atoms and 6 O atoms)

You might be interested in

Convert 2.8 pounds to kg

Pani-rosa [81]

Answer:

1.27006 kg

Explanation:

1 lb is equal to 0.907185 kg

5 0

4 years ago

Read 2 more answers

If your front lawn is 18.0 feet wide and 20.0 feet long. And each square foot of lawn accumulates 1450 new snow flakes every min

creativ13 [48]

To solve this problem, we begin by first calculating the area of the front lawn. The length and width of the lawn was given and the area of a rectangle is given by the formula: Area = length x width. Thus, the area of the front lawn can be obtained by multiplying 18 ft by 20 ft, wherein we get 360 ft^2 as the area.

Second, the problem indicated that each square foot of lawn accumulates 1450 new snow flakes per minute. This can be translated into the expression 1450 snow flakes/ (minute·ft^2). In this way, we can convert it to units of mass (kg). Afterwards, we simply need to multiply it to the area of the lawn and convert minute to hour. The following expression is then used:

1450 snow flakes/ (minute·ft^2) x 1.90 mg/snow flake x 1 g/1000 mg x 1kg/1000 g x 360 ft^2 x 60 minutes/hour = 59.508 kg snow flake/hour

It is then calculated that 59.508 kg of snow flake accumulates in the lawn every hour.

6 0

3 years ago

Can someone help me pls

Inessa [10]

Answer:

The heat would flow from the hot solid to the cool solid until all temperatures are near equal.

4 0

3 years ago

he chlorination of methane occurs in a number of steps that results in the formation of chloromethane and hydrogen chloride. The

frez [133]

Answer:

The total pressure in the flask is 0,619 atm.

Explanation:

For the reaction:

2CH₄(g) + 3Cl₂(g) → 2 CH₃Cl(g) + 2HCl(g) + 2Cl⁻(g)

The moles of CH₄ in 295 mL at STP are:

n = PV/RT

Where P is pressure (1 atm), V is volume (0,295L), R is gas constant (0,082atmL/molK) and T is temperature (273,15 K)

Replacing, moles of CH₄ are 0,0132 moles

In the same way, moles of chlorine are 0,0324 moles

As 3 moles of Cl₂ react with 2 moles of CH₄, for a total reaction of 0,0132 moles of CH₄ you need:

0,0132 moles CH₄ × $\frac{3 mol Cl_{2}}{2 mol CH_{4}}$ = 0,0198 moles Cl₂. That means that 0,0324-0,0198 = -0,0126 moles of Cl₂ are in excess-.

As the reaction reaches in 77%, the moles of CH₄ that don't react are:

0,0132×(100%-77%)= 3,036x10⁻³ moles of CH₄

Also, the moles of Cl₂ that don't react are:

0,0126 + 0,0198×(100%-77%)= 0,0172 moles of Cl₂

The moles produced of each compound are:

0,0132×77% moles × $\frac{2 mol CH_{3}Cl}{2 mol CH_{4}}$ = 0,0102 moles of CH₃Cl -that are the same moles of HCl and Cl⁻-

Thus, total moles in the flask are:

3,036x10⁻³ moles of CH₄ + 0,0172 moles of Cl₂ + 0,0102 moles of CH₃Cl + 0,0102 moles of HCl + 0,0102 moles of Cl⁻ = 0,0507 total moles

As the volume of the flask is 2,00L and the final temperature is 298 K. The total pressure in the flask is:

P = nRT/V

P = 0,619 atm

I hope it helps!

5 0

4 years ago

Ann propped up a graham cracker in a shallow bowl. She then set up an electric fan to blow on the graham cracker at three differ

neonofarm [45]

The dependent variable is the graham cracker.

6 0

4 years ago

Read 2 more answers