How many protons and electrons are present in a barium atom?

1 answer:

6 0

To solve this problem, we can look it up on the periodic table.

Barium has a mass number of 56, also the 56th element on the table. Mass number actually is equal to the number of protons, proton number of an element is like an ID card number, which no other elements have the same. So, the number of protons is 56.

Electrons of an atom equals to the number of proton too. So the number of electrons of barium atom is also 56. If the number of electrons is changed, the atom is no longer an atom, it'll become ions.

So yes, both answer is 56.

You might be interested in

30 point. What is formed when a hydroxyl group is substituted for a hydrogen?

Andru [333]

Haloalkanes

Yeah it’s that

6 0

3 years ago

How to solve this: a small dog has consumed a dangerous amount of apap. the vet has ordered: rx acetylcysteine 150mg/kg/stat. yo

Fantom [35]

Given:
Stock dose/concentration of 20% Acetylcysteine (200 mg/mL)
150 mg/kg dose of Acetylcysteine
Weight of the dog is 13.2 lb

First we must convert 13.2 lb to kg:
13.2 lb/(2.2kg/lb) = 6 kg

Then we must calculate the dose:
(150 mg/kg)(6kg) = 900 mg

Lastly, we must calculate the dose in liquid form to be administered:
(900 mg)/(200 mg/mL) = 4.5 mL

Therefore, 4.5 mL of 20% Acetylcysteine should be given.

3 0

3 years ago

The theory used to explain the behavior of solids, liquids and gases is

Annette [7]

<span>Kinetic molecular theory.

</span>

5 0

3 years ago

How many liters of carbon dioxide will be produced at STP if 3.56 g calcium carbonate reacts completely with carbon dioxide? CaC

sp2606 [1]

Answer:

V = 0.798 L

Explanation:

Hello there!

In this case, for this gas stoichiometry problem, we first need to compute the moles of carbon dioxide via stoichiometry and the molar mass of starting calcium carbonate:

$3.56gCaCO_3*\frac{1molCaCO_3}{100gCaCO_3} *\frac{1molCO_2}{1molCaCO_3} =0.0356molCO_2$

Next, we use the ideal gas equation for computing the volume, by bearing to mind that the STP conditions stand for a pressure of 1 atm and a temperature of 273.15 K:

$PV=nRT\\\\V=\frac{nRT}{P}\\\\V=\frac{0.0356mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm} \\\\V=0.798L$

Best regards!

4 0

3 years ago

Suggest why it might be difficult and dangerous to test sodium for electrical conductivity?

lukranit [14]

Answer:

It might cause fire or extreme smoke.

Explanation:

8 0

3 years ago