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mart [117]
3 years ago
8

Write a scientific explanation of conduction.

Chemistry
2 answers:
igor_vitrenko [27]3 years ago
7 0

Answer:

Conduction is the process by which heat energy is transmitted through collisions between neighboring atoms or molecules.

Explanation:

These vibrating molecules collide with their neighboring molecules, making them also vibrate faster. As these molecules collide, thermal energy is transferred via conduction to the rest of the pan.

Hope this helps!

Sloan [31]3 years ago
6 0
Conduction is the process by which heat energy is transmitted through collisions between neighboring atoms or molecules! Hope this helps!!
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7 0
3 years ago
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2.40 kJ of heat is added to a slug of platinum and a separate 2.40 kJ of heat is added to a slug of zinc. The heat capacity of t
leonid [27]

Final temperature of platinum :-   36.5°C

Final temperature of Zinc :-  29.17°C


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3 years ago
EASY QUICK CHEM QUESTION!! Which line indicates a higher reaction rate?
ad-work [718]
2. B because it has a lower activation energy.

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3 0
3 years ago
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What can you conclude about red visible light waves compared to blue visible light waves?
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Explanation:

On comparing blue visible light with red visible light, there is difference in the wavelength, frequency, and energy. The difference between both red and blue visible lights are as follows.

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7 0
3 years ago
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Suppose 11.4g of ammonium chloride is dissolved in 250 ml of a 0.3M aqueous solution of potassium carbonate. Calculate the final
Sindrei [870]

Answer:

The molarity of the final ammonium cation is 0.252M

Explanation:

<u>Step 1:</u> Data given

Mass of ammonium chloride (NH4Cl) = 11.4 grams

Volume of 0.3 M aqueous solution of potassium carbonate (K2CO3) = 250 mL = 0.250L

<u>Step 2:</u> The balanced equation

2NH4Cl + K2CO3 → 2KCl + (NH4)2CO3

<u>Step 3:</u> Calculate moles of (NH4)Cl

moles (NH4)Cl = 11.4 grams /53.49 g/mol

Moles (NH4)Cl = 0.213 moles

<u>Step 4: </u>Calculate moles of K2CO3

Moles K2CO3 = Molarity * Volume

Moles K2CO3 = 0.3M * 0.250 L = 0.075 moles

<u>Step 5:</u> Calculate moles (NH4)Cl at the equilibrium

For 2 moles (NH4)Cl consumed, we need 1 mole of K2CO3 to produce 2 KCl and 1 mole of (NH4)2CO3

(NH4)2CO3l will dissolve in 2NH4+ + CO32-

Moles (NH4)2Cl = 0.213 moles - 2*0.075 = 0.063 moles

Moles NH4+ = moles (NH4)Cl = 0.063 moles

<u>Step 6:</u> Calculate Molarity of NH4+

Molarity = Moles / volume

Molarity of NH4+ = 0.063 moles / 0.250 L

Molarity of NH4+ = 0.252 M

The molarity of the final ammonium cation is 0.252M

5 0
3 years ago
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